<span>The function which has a constant halving time is in the following form
</span>

Where: A₀ is the <span>initial amount
h is the half life time or the halving time.
</span><span> t is the time
</span> A(t) <span>the amount<span> that remains at time t
</span></span>
The previous function represents an Exponential decay<span> function.
</span>
so, The correct answer is option B. <span>
Exponential decay</span>
Answer:
2/5
Step-by-step explanation:
1/10 times 4
4/10 equals to 2/5
Answer:
Q1) (x+7)² = 9
x = -10, -4
Q2) (x-8)² = 144
x = -4, 20
Q3) (x-1)² = 81
x = -8, 10
Step-by-step explanation:
Q1) x² + 14x + 49 = 9
x² + 2(x)(7) + 7² = 9
(x + 7)² = 9
x + 7 = +/- sqrt(9)
x + 7 = 3
x = -4
x + 7 = -3
x = -10
Q2) x² - 16x + 64 = 144
x² - 2(x)(8) + 8² = 144
(x - 8)² = 144
x - 8 = +/- sqrt(144)
x - 8 = 12
x = 20
x - 8 = -12
x = -4
Q3) x² - 2x + 1 = 81
x² - 2(x)(1) + 1² = 81
(x - 1)² = 81
x - 1 =+/- sqrt(81)
x - 1 = 9
x = 10
x - 1 = -9
x = -8
1. 2/3 - (1/4)*(4/9)
2/3-4/36
24/36-4/36
20/36 also same as 4/9 (D)
2. It's B. (-3*(2*7)=(-3*2)*7
3. -4+(-6)*(-3)
-4+18
-14 (b)