I’ve been stuck on this question for a while can someone help please
1 answer:
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Answer:
No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)
Step-by-step explanation:
The triangle has vertices A(1,1), B(5,1), C(3,4).
First transformation is reflection over y-axis with the rule
(x,y)→(-x,y)
so,
- A(1,1)→A'(-1,1)
- B(5,1)→B'(-5,1)
- C(3,4)→C'(-3,4)
Second transformation is rotation by 270° counterclockwise with the rule
(x,y)→(y,-x)
so
- A'(-1,1)→A''(1,1)
- B'(-5,1)→B''(1,5)
- C'(-3,4)→C''(4,3)
No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)
