Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
x = 30
Step-by-step explanation:
Answer:
b. 3 1/4
Step-by-step explanation:
Answer:
<h3>Q1</h3>
- This is acute angle since 75° < 90°
<h3>Q2</h3>
- This is an isosceles triangle
<h3>Q3</h3>
<u>Exterior angle is the sum of non-adjacent interior angles:</u>
- 4x + 7 + 6x - 9 = 118
- 10x - 2 = 118
- 10x = 120
- x = 12
m∠L = 4*12 + 7 = 48 + 7 = 55°
<h3>Q4</h3>
<u>The triangles are congruent and corresponding sides are equal:</u>
- 3x - 5 = 2x + 1
- 3x - 2x = 1 + 5
- x = 6
<u>Side lengths are:</u>
The length of the sides is 6
