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4 years ago

The base of a regular pyramid is a hexagon.

Mathematics

2 answers:

dedylja [7]4 years ago

6 0

Answer:

96sqrt(3)

Step-by-step explanation:

Simplest and most intuitive way is to find area of 1 triangles and multiply it by 6.

Area of one triangle:

base = 8 and a = 4sqrt(3)

Area of 1 trangle = ba/2

Area of base of hexagon = 6 times that.

FrozenT [24]4 years ago

6 0

<u>Answer:</u>

$72\sqrt{3} cm^2$

<u>Step-by-step explanation:</u>

We are given that the base of a regular pyramid is a hexagon and we are to find the area of the base (which is a hexagon).

We know that the formula for the area of hexagon is given by:

$A = \frac { 3 \sqrt { 3 } } { 2 } a^2$

We are to find the value of a to find this area.

Finding a:

$sin 60=\frac{a}{8}$

$a=6.92$

Substituting this value of $a$ in the above formula to get:

Area of the base (hexagon) = $\frac { 3 \sqrt { 3 } } { 2 } \times 48 (6.92)^2$ = $72\sqrt{3} cm^2$

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Salsk061 [2.6K]

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$\large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }$

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6 0

3 years ago

Read 2 more answers

H(t)=(t+3)^2+5

sineoko [7]

Answer:

Option C. −4≤t≤−3

Step-by-step explanation:

we have

$H(t)=(t+3)^2+5$

This is the equation of a vertical parabola written in vertex form

The parabola open upward (the leading coefficient is positive)

The vertex is a minimum

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The function is increasing in the interval [-3,∞)

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The function will have a negative average rate when the function will be decreasing

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4 years ago

The teacher wanted to know what the average test grade was, so she added up all the grades and divided by the number of tests to

svp [43]

Answer:

Mean

Step-by-step explanation:

Adding up and dividing to find the mean.

We simply add up all of the individual grades, get the total, and then divide by the number of students in the class.

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3 years ago

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Georgia [21]

7/12 = 0.84
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3 years ago

Researchers are investigating whether people who exercise with a training partner have a greater increase, on average, in target

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Answer:

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Past excercising habits may affect the change in intensity to a targeted excersise in different manner. So in method I a greater diversity is included and result of excersing with or without a trainer will account for greater number of variables than method II.

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3 years ago