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dybincka [34]
3 years ago
5

What is the area of the obtuse triangle given below?

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0
Hey! there isn’t a pic posted, but if you post it again with the photo included i’m happy to answer it:)
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Can someone help me with this problem involving factoring a trinomial and filling in a table? Steps 1, 2, and 3 please. Thank yo
oksano4ka [1.4K]

Step 1 involves you listing out all the ways to multiply to 56, and then adding up those factors. For instance, the first row has 1 and 56 which add to 57 in the third column. The second row has -1 + (-56) = -57. The third row has 2+28 = 30. And so on. The idea is to fill out the table completely with the other ways to have factors of 56 added up. The table is shown in the attached image below.

------------------

Step 2 then uses the table to figure out which pair of factors (of 56) add to -15. This would be -7 and -8. In other words,

-7 plus -8 = -15

-7 times -8 = 56

We have found the right pair of numbers. In the table I have provided, this is shown as the highlighted yellow row.

------------------

Step 3 is then using those pair of numbers found in step 2 to set up the factorization. We would say that x^2-15x+56 factors to (x-7)(x-8). This is the same as (x-8)(x-7) as we can multiply two numbers in any order we want.

6 0
3 years ago
If 5=3+2,then 3+2=5. What is the truth value
olga nikolaevna [1]

Answer:

true

Step-by-step explanation:

6 0
3 years ago
A road is
Airida [17]

9514 1404 393

Answer:

  25/42 mi

Step-by-step explanation:

5/6 of 5/7 of a mile is ...

  (5/6)(5/7 mi) = 25/42 mi

4 0
4 years ago
HELP PICS INCLUDED! WILL GIVE BRAINLIEST! SHOW WORK AND EXPLAIN
Naddik [55]

I assume you know about the dot product, and that for two vectors \mathbf a and \mathbf b, the angle between them \theta satisfies

\mathbf a\cdot\mathbf b=\|\mathbf a\|\|\mathbf b\|\cos\theta\iff\cos\theta=\dfrac{\mathbf a\cdot\mathbf b}{\|\mathbf a\|\|\mathbf b\|}

Then the vectors are parallel if the angle between them is 0 or 180 degrees (0 or pi radians), which would make \cos\theta=1 or \cos\theta=-1, respectively.

Part A)

\vec v_1=\langle\sqrt3,1\rangle\implies\|\vec v_1\|=\sqrt{(\sqrt3)^2+1^2}=\sqrt4=2

\vec v_2=\langle-\sqrt3,-1\rangle=-\vec v_1\implies\|\vec v_2\|=\|\vec v_1\|=2

\vec v_1\cdot\vec v_2=(\sqrt3)(-\sqrt3)+(1)(-1)=-4

Then the angle between \vec v_1,\vec v_2 is such that

\cos\theta=\dfrac{-4}{(2)(2)}=-1\implies\theta=\pi\,\mathrm{rad}

so these vectors are parallel ("antiparallel", more specifically, which means they are parallel but point in opposite directions).

Part B) involves the same computations:

\vec u_1=\langle2,3\rangle\implies\|\vec u_1\|=\sqrt{2^2+3^2}=\sqrt{13}

\vec u_2 has the same components but differing by sign and order, as \vec u_1; its magnitude remains the same, though:

\vec u_2=\langle-3,-2\rangle\implies\|\vec u_2\|=\sqrt{(-3)^2+(-2)^2}=\sqrt{13}

\vec u_1\cdot\vec u_2=(2)(-3)+(3)(-2)=-12

\implies\cos\theta=\dfrac{-12}{(\sqrt{13})(\sqrt{13})}=-\dfrac{12}{13}\implies\theta=\cos^{-1}\left(-\dfrac{12}{13}\right)

which is neither 0 nor pi, which means these vectors are not parallel.

4 0
4 years ago
A tower casts a shadow that is 60 feet long when the angle of elevation of the sun is 65 degrees. How tall is the tower?
Margaret [11]

Answer:

128.67 feet

Step-by-step explanation:

We would be solving this question using the Trigonometric function of tan.

Tan( of the angle of elevation) = height of the tower ÷ height of the shadow.

Angle of elevation = 65°

Height of the tower = unknown, which is designated as X

Height of the shadow = 60 feet.

Therefore,

tan 65° = X/ 60 feet

We crossmultiply

X = tan 65° × 60 feet

X = 128.67041523 feet.

Approximately, X = 128.67 feet.

Therefore, the tower is 128.67 feet tall.

7 0
4 years ago
Read 2 more answers
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