Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
The function would be the initial plus growth rate * # years
So: f(x) = 9.05 + 0.031(7)
Where x= # years
Answer:
(x - 2)² - 30
Step-by-step explanation:
To complete the square
add/subtract ( half the coefficient of the x- term )² to x² - 4x
f(x) = x² + 2(- 2)x + 4 - 4 - 26 = (x - 2)² - 30
<span>There is a 20% (or 20/100chance) it will rain on Thursday and there is a 40% (or 40/100) chance it will rain on Friday. In order to find out the probability of it raining both days, we need to multiply these two values. (40/100)(20/100)= 800/10,000= 0.08. We move the decimal over two places to get a percent, so we get an 8% chance it will rain on both Thursday and Friday.</span>
X is 12, I did this question to someone else before
