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gizmo_the_mogwai [7]

3 years ago

10

How do you factor an expression? For example,

" align="absmiddle" class="latex-formula">

1 answer:

Inga [223]3 years ago

8 0

Answer:

Step-by-step explanation:

The greatest common factor is the greatest factor common to all terms. An expression is completely factored when no further factoring is possible. The possibility of factoring by grouping exists when an expression contains four or more terms. The FOIL method can be used to multiply two binomials

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What is the equation? Pls show your work.

Semmy [17]

Answer:

y=2x-2

Step-by-step explanation:

y=mx+b is point slope form.

let m= the slope

b=y intercept

the y intercept is -2

y=mx-2

then after finding the slope (2) put that in

y=2x-2

4 0

3 years ago

hat are the solutions to the equation |x| = 2? Choose all answers that are correct. A. B. C. D.

zalisa [80]

Easy, so absolute value makes anything inside into positive
|x|=2
therefor x=-2 or x=2 since it would be made posotive

answer is -2 and 2

6 0

3 years ago

Read 2 more answers

Convert 312 quarts to gallons.

dimaraw [331]

78 gallons is the same as 312 quarts

8 0

3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Item 16 A sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. What is the difference of the vol

Zigmanuir [339]

Answer:

$672\pi \text{ cm}^3$ .

Step-by-step explanation:

We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.

We will use volume formula of sphere to solve our given problem.

$\text{Volume of sphere}=\frac{4}{3}\pi r^3$ , where r is radius of sphere.

The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

$\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512)\text{ cm}^3-\frac{4}{3}\pi(8)\text{ cm}^3$

$\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3$

$\text{Difference of volumes}=4\pi(168)\text{ cm}^3$

$\text{Difference of volumes}=672\pi\text{ cm}^3$

Therefore, the difference between volumes of the spheres is $672\pi \text{ cm}^3$ .

3 0

3 years ago