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Vikki [24]
3 years ago
5

Determine weather the given values are from a discrete or continuos data set. A statistics student obtains a sample data from on

e of his classes and finds that the average student weighs 157.0 lbs
Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0

A continuous data set is where you can plot every point (even very, very small decimal numbers) because the unit can be measured in parts of the whole.

A discrete data set is where you can only plot the units in whole values. For example, if you were plotting the number of people, you can't have a part of a person.

Weight is measured in lbs which can be measured in parts of the lb (such as 100.005 lbs) so it is continuous.

Answer: Continuous data set

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T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


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{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

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x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

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k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
Someone please convert this equation to slope intercept form: 2x - 3y = 6?
IgorLugansk [536]
Slope y-intercept form is: y=mx+b

All you have to do is rearrange the equation:

2x-3y=6
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now divide both sides by 3
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and it becomes
y= \frac{2}{3}x-2x

Bonus: you can plug in any two values for x and y and you can see both equation gives the same answer!
8 0
3 years ago
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