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Alina [70]
3 years ago
8

Where can you find your EFC

Computers and Technology
2 answers:
Leto [7]3 years ago
5 0

In your SAR

Explanation:

The answer for Apex

netineya [11]3 years ago
3 0

EFC stands for Expected Family Contribution (EFC) and denotes the amount you and your parents can be expected to contribute to your college costs based on the information collected by the FAFSA (Free Application for Federal Student Aid). You can find your EFC is  on your Student Aid Report (SAR).

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Besides a soho router, which of these devices is a network printer most likely to be connected to? a. router b. server c. workst
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2 years ago
Read 2 more answers
Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t
Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

4 0
2 years ago
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