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3 years ago

Determine the following for the transformed cosine

Mathematics

2 answers:

denis23 [38]3 years ago

7 0

Answer:

See Picture. Hope This Helps

Step-by-step explanation:

Verdich [7]3 years ago

5 0

Answer:

1/1080

1/3

y=cos(x/3)

Step-by-step explanation:

just did it

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Help will give brainliest!!!!!!

sashaice [31]

Answer:

2.5

type A/B

Step-by-step explanation:

10/2.5=4

15/6=2.5

18/7.2=2.5

7 0

3 years ago

The mass of a freight train is 9.98 ⋅ 106 kilograms. The mass of an aircraft carrier is 7.3 ⋅ 107 kilograms. Approximately how m

shutvik [7]

Mass of freight train: 9.98 • 106
= 1057.88 kg
mass of aircraft carrier: 7.3 • 107
= 781.1 kg
difference: 1057.88 - 781.1
= 276.78 kg
= 2.7678 x 10^2

8 0

2 years ago

One antifreeze solution is 20% alcohol. Another antifreeze solution is 12% alcohol. How many liters of each solution should be c

katrin [286]

Use this systems of equations to solve:

x = first antifreeze
y = second antifreeze

$\left \{ {{.2x + .12y = .18(15)} \atop {x + y = 15}} \right.$

Isolate y.

x + y = 15
Subtract x from both sides.
y = -x + 15

Substitute y into the other equation.

.2x + .12(-x + 15) = .18(15)
Simplify.
.2x - .12x + 1.8 = 2.7
Subtract 1.8 from both sides.
.08x = .9
Divide both sides by .08
x = 11.25

Substitute x in the equation that we isolated y in.

y = -11.25 + 15
y = 3.75

11.25 L of the first antifreeze and 3.75 L of the second.

5 0

3 years ago

two friends are renting an apartment. they pay the landlord the first and last month's rent. the landlord also requires them to

GarryVolchara [31]

Use the given information to write an equation, then solve it.

$1600 = (1 + 1 + 1/2)×(monthly rent) . . . . relationship given in the problem statement

$1600/2.5 = monthly rent = $640 . . . . divide by the coefficient of monthly rent

3 0

3 years ago

Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.

FrozenT [24]

You have shared the situation (problem), except for the directions: What are you supposed to do here? I can only make a educated guesses. See below:

Note that if   <span>ax^2+bx+5=0 then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers. If this is the case, then the discriminant, b^2 - 4(a)(c), must be positive. Since c = 5,

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

- b plus sqrt( b^2 - 20a )
d =  ------------------------------------
2a

and

</span> - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b." Before going into that, however, I'm asking you to share the rest of the problem statement. What, specificallyi, were you asked to do here?

7 0

3 years ago