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Lelu [443]
3 years ago
8

Solve by factoring.

Mathematics
1 answer:
Ronch [10]3 years ago
6 0
The answer is A. Risvfnishfiwbxhfjbsvsjsk
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What is the area of a triangle whose vertices are D(3,3) , E(3,−1) , and F(−2,−5)?<br> ?= Unit ^2
Thepotemich [5.8K]
Length of DE = 3-(-1) = 4

SIDE DE is a vertical line 

horizontal distance between E and F is  3 - (-2) = 5

So the area of triangle DEF = 0.5 * 4 * 5 = 10 sq units
5 0
3 years ago
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Necesito encontrar expresiones equivalentes a los valores del 1 al 20 pliss
Mariulka [41]

Answer and Step-by-step explanation:

Si está buscando una expresión que sea igual a los números del 1 al 20, intente hacer una. Por ejemplo, 2y + 1x = 18 donde y = 9 - x / 2 y x = 18 - 2y. Siempre que la expresión sea igual a menos de 20, ¿no?

Lo siento, no entendí muy bien la pregunta, ¡pero espero que esto te haya ayudado! ¡Ten un día maravilloso! <3

**Tenga en cuenta que mi español no es el mejor, lo siento mucho, hablo principalmente inglés. Mi mal, con suerte, me puedes entender.**

4 0
3 years ago
Which expression is equivalent to x + y + x + y + 3(y + 5)? 2x + 5y + 5 2x + y + 30 2x + 5y + 15 2x + 3y + 10 NextReset
jolli1 [7]
<span>Which expression is equivalent to x + y + x + y + 3(y + 5)? 2x + 5y + 5 2x + y + 30 2x + 5y + 15 2x + 3y + 10 

</span>x + y + x + y + 3(y + 5)=  \\  \\ x+y+x+y+3y+15=   \boxed{ 2x+5y+15 }<span>
</span>
7 0
3 years ago
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7 1/2 - 6 3/10 find the differnce
tigry1 [53]

Answer: they are different numbers

Step-by-step explanation:

7 0
3 years ago
F(x) = 2x^2 − 3x − 5 Part
riadik2000 [5.3K]

Answer:  Answer  is in the steps..

Step-by-step explanation:

f(x)= 2x^{2} - 3x -5        

A) To find the x intercepts of a parabola we have to set the whole equation equal zero because the x intercept is when y equal zero in other words where f(x) equal zero.

 2x^{2}  - 3x - 5 = 0     Now solve using quadratic formula.

  x = -b±\frac{\sqrt{b^2 -4ac } }{2a}    

  x = 3 ± \sqrt{9+40} /2a  

   x = 3 ± \sqrt{49}  / 2a

   x= 3 ± 7 /4

   x= -1   or x = 5/2  

The x intercepts are  (5/2,0)  and (-1,0)

   

B)  The graph vertex of the graph of f(x)  is going to be at a minimum because the leading coefficient of the function has a positive integer which means the parabola will open up and its vertex will be at the minimum point.

 Using the  x coordinates  we could find their average and find the x coordinate of the   vertex.

\frac{5}{2} + -\frac{1}{1}  =  \frac{3}{2} / \frac{2}{1} = 3/4  

The x coordinate of the vertex  is 3/4 so we will input that into the equation and solve for the y coordinate  

2(\frac{3}{4})^2 - 3 (\frac{3}{4}) - 5   = 18/16 - 9/4 -5  =  -49/8

The y coordinate of the vertex  is  -49/8

So the vertex is (3/4, -49/8)  

C)   First  I will graph the vertex and then graph he two x intercepts and connect then like a U shape.

5 0
4 years ago
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