Answer:30
Step-by-step explanation: Put 30 times 15 into a calulater. Then do 15 times 2 then you find your answer.
Step-by-step explanation:
Pythagoras' theorem for the smallest one :
= 52
Pythagoras' theorem for the middle one :
= 
+ 
Pythagoras' theorem for the biggest one :
Using the formula before (for 
) it becomes :
16 + 8a = 52 + 36
16+8a = 88
8a = 88-16
8a = 72
a = 9
Verifying :
= 117
The biggest one :
True
Only one. These problems always have one solution unless something has changed.
Answer:
4
Step-by-step explanation:
Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:
CW = UCL - LCL
Where,
CW= Class width
UCL= Upper class limit
LCL= Lower class limit
From the table above:
For class 1, CW = 64 - 60 = 4
For class 2, CW = 69 - 65 = 4
For class 3, CW = 74 - 70 = 4
For class 4, CW = 79 - 75 = 4
For class 5, CW = 84 - 80 = 4
Therefore, the class width of the grouped data = 4
Answer: 3/5
Step-by-step explanation: 3/5 is equal to .6 so if is greater than .5625
