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nevsk [136]
3 years ago
10

If nick gets out of svhool at 2:25 and has a 15 minute ride home and goes has a 30 minute bick ride then speands 55 minutes doin

g homework. What time will he finish his homework?
Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:

4:05 PM / 16:05

Step-by-step explanation:

Time starts at 2:25.

After the ride home (15 minutes), it will be 2:40.

Then, after the bike ride it will be 3:10.

When he's finished with his homework, it will be 4:05.

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Help asap help please.
Xelga [282]

Answer:

30(x+1)/(x+7)

Step-by-step explanation:

This is not a rational expression because denominator has a domain of which it can be undefined.

To rationalize multiply by the reciprocal of the denominator (1/6+1/x+1)

___<u>5___ </u>*(6)(x+1) --> _____<u>30(x+1)_____</u> --><u> 30x+1</u>_ --> <u>30x+1</u>

1/6+1/x+1   *(6)(x+1)--> 6(x+1)/6 + 6(x+1)/(x+1) --> (x+1)+6 --> x+7

Final Answer: 30(x+1)/(x+7)



7 0
3 years ago
Suppose you waited 10 years to invest in the same retirement fund and have the same $400,000 for retirement at the same 8% inter
Ierofanga [76]

Answer:

<em>$7,196.42 </em>

Step-by-step explanation:

Using the compound interest formula to fins the amount after 10years;

A  = P(1+r)^n

Principal P = $400,000

Rate r = 8% = 0.08

Time t = 10 years

Substitute

A = 400,000(1+0.08)^10

A = 400,000(1.08)^10

A = 400,000(2.1589)

A = 863,569.99

A ≈ 863,570

Hence the amount after 10 years is $863,570

Monthly deposit = $863,570/120 (10 years is equivalent to 120months)

Monthly deposit = 7,196.42

<em>Therefore he will have to deposit $7,196.42 into his account monthly</em>

7 0
2 years ago
4 2/5 Times 10 what is it
Anettt [7]
44 is the answer to 4 2/5 times 10.
8 0
3 years ago
Ellen bought 3 greeting cards for $3 each.
Ne4ueva [31]

Answer:

(3×3)+2=11

$11

Step-by-step explanation:


5 0
3 years ago
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
2 years ago
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