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Tresset [83]
2 years ago
14

Solve the equation. (x-5)(x+3)=0

Mathematics
2 answers:
LuckyWell [14K]2 years ago
8 0
(x-5)(x+3)=0
x^2+3x-5x-15=0
(x^2+3x) (-5x-15)
x(x+3) -5(x+3)
x-5=0 x+3=0
x=5 OR -3
hammer [34]2 years ago
5 0

Answer:

The solutions to the equation are x=5 x=-3

Step-by-step explanation:

(x-5)(x+3)=0

Since this is already factored, we can use the zero product property to determine the roots

x-5 =0                x+3 =0

x-5+5= 0+5        x+3-3 = 0-3

x =5                   x=-3

The solutions to the equation are x=5 x=-3

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

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Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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This means that p = \frac{99}{99+78} = 0.5593

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a. Calculate the probability of getting more than 61% green balls.

This is 1 subtracted by the pvalue of Z when X = 0.61. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.61 - 0.5593}{0.0373}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131

1 - 0.9131 = 0.0869

0.0869 = 8.69% probability of getting more than 61% green balls.

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