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3 years ago

What is five times the difference of a number and three? Btw I need answer immediately

Mathematics

2 answers:

tankabanditka [31]3 years ago

8 0

Answer:

t=x+3

y = (x+3)^2 + 5

y = x^2+6x + 9 + 5

y= x^2 + 6x + 14

IrinaK [193]3 years ago

6 0

Answer:

5 times x-3?

Step-by-step explanation:

Sorry if its wrong i didn't really understand what you wanted.

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Which of these numbers is composite? 41,77,83,89,97

makvit [3.9K]

Answer:

It's 41

Step-by-step explanation:

Therefore all numbers that end with five and are greater than five are composite numbers.

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I need help with a problem with solving by square roots in quadratic equation.

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To solve for x, first, we add 3 to the given equation:

$\begin{gathered} 2(x+5)^2-3+3=44+3, \\ 2(x+5)^2=47. \end{gathered}$

Dividing by 2, we get:

$(x+5)^2=\frac{47}{2}.$

Therefore:

$x+5=\pm\sqrt{\frac{47}{2}}.$

Finally, subtracting 5 we get:

$x=\pm\sqrt{\frac{47}{2}}-5.$

Answer:

$x=\operatorname{\pm}\sqrt{\frac{47}{2}}-5.$

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2 years ago

Find the perimeter of the sector of a circle of radius 14cm with an angle of 72 degree

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Answer:

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3 years ago

Point: (-3, 7); Slope: 4

GaryK [48]

Answer:

y - 7 = 4(x + 3)

Step-by-step explanation:

Write the equation of a line using the point slope formula. Substitute m = 4 and the point (-3,7) in the formula.

$y - y_1 = m(x-x_1)\\y - 7 = 4(x--3)\\y - 7 = 4(x+3)$

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3 years ago

Somebody please help with this problem

Mrrafil [7]

Step-by-step explanation:

We have been given that AE=BE and $\angle1\cong \angle2$ .

We can see that angle CEA is vertical angle of angle DEB, therefore, $m\angle CEA=m\angle DEB$ as vertical angles are congruent.

We can see in triangles CEA and DEF that two angles and included sides are congruent.

$\angle 1\cong \angle 2$

$AE=BE$

$\angle CEA\cong\angle DEB$ or $\angle 3\cong \angle 4$

Therefore, $\Delta CEA\cong \Delta DEB$ by ASA postulate.

Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.

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3 years ago