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stepladder [879]
3 years ago
13

Multiply the bottom h's. \frac{6h ^{2} }{2h ^{8}h h}

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
5 0
\frac{6h ^{2} }{2h ^{8}h h}= = \frac{6h^2}{2h^8h^2} = \frac{6h^2}{2h^{10}} = \frac{3h^2}{h^{10}} = \frac{3}{h^8} = \boxed{\boxed{\bf{3h^{-8}}}}
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