What unit do we use to measure angles??
2 answers:
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Bernard’s walking speed is 140 meters per minute
Bernard’s walking speed is 8.4 kilometers per hour
Step-by-step explanation:
The pace length P is the distance between the rear of two consecutive footprints
The formula, n P = 140, gives an approximate relationship between n and P where,
- n = number of steps per minute
- P = pace length in meters
- Bernard knows his pace length is 0.80 meters
- The formula applies to Bernard’s walking
We need to calculate Bernard’s walking speed in meters per minute and in kilometers per hour
∵ n = number of steps per minute
∴ n unit is number / minute
∵ P = pace length in meters
∴ P unit is meter
- That means n P unit is meters/minute
∴ n P represents the speed in meters per second
∵ The formula applies to Bernard’s walking
∵ His pace length is 0.80 meters
∵ n P = 140
∴ n(0.8) = 140
- Divide both sides by 0.8
∴ n = 175
- That means he moves 175 steps per minute
∵ The distance he walks in minute = 175 × 0.8 = 140 meters/minute
∴ His speed is 140 meters per minute
Bernard’s walking speed is 140 meters per minute
∵ 1 km = 1000 m
∵ 1 hour = 60 minutes
- Divide the meters by 1000 and the minute by 60 to change
from meters per minute to kilometers per hour
∴ His walking speed = ÷
- Change ÷ to × and reciprocal the fraction after the division sign
∴ His walking speed = ×
= 8.4 km/h
Bernard’s walking speed is 8.4 kilometers per hour
Learn more:
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Answer:
∠EGB and ∠AGF are congruent;
Transitive Property of Equality
Step-by-step explanation:
The vertical angles theorem is about the angles that are opposite to each other. These angles are formed when two lines cross each other
Vertical angles are congruent i.e their measures are equal
Look at the attached graph
Given:
AB // CD
E , G , H , F are col-linear
The line which contains points E , G , H , F is a transversal for the parallel lines AB and CD
∵ AB and EF intersected at point G
∴ m∠EGB = m∠AGF ⇒ by the vertical angles theorem
When lines AB and EF intersected at G they formed opposite angles like angles EGB and AGF, then angles EGB and AGF are congruent ( vertical angle theorem)
∵ AB // CD and EF is a transversal
∴ m∠AGF = m∠CHF (corresponding angles theorem)
Transitive Property of Equality: if one angle is equal to two other angles, then the two other angles are equal
Therefore, If a = b and b = c, then a = c
∵ m∠EGB = m∠AGF
∵ m∠AGF = m∠CHF
∴ m∠EGB = m∠CHF (transitive property theorem)
∠EGB and ∠AGF are congruent; Transitive Property of Equality
