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3 years ago

What equals 44 in multiplication?

Mathematics

1 answer:

lutik1710 [3]3 years ago

3 0

22 times 2, 44 times 1, and 11 times 4 those are some examples. Hope this Helps! :D

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The product of the reaction between ethanal and ammonia are what.

kenny6666 [7]

Answer:

Step-by-step explanation:

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3 years ago

Margaret has 16 yards of fabric and she is making dresses for z doll write the expression for the length of fabric used for each

emmasim [6.3K]

<h3>The expression for the length of fabric used for each doll is $\frac{16}{z}\ yards$ </h3>

<em><u>Solution:</u></em>

Given that,

Margaret has 16 yards of fabric

she is making dresses for z doll

Therefore,

Total length of fabric = 16 yards

Number of dresses = z dolls

Therefore,

$\text{ length of fabric used for each doll } = \frac{ \text{ Total length of fabric }} {\text{ z dolls }}\\\\\text{ length of fabric used for each doll } = \frac{16}{z}\ yards$

Thus, the expression for the length of fabric used for each doll is $\frac{16}{z}\ yards$

7 0

3 years ago

In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel

Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

Now,

change in sulfur oxide with time i.e $\frac{\textup{dS}}{\textup{dt}}$

differentiating the given relation with respect to time 't'

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = $2\times110P\frac{\textup{dP}}{\textup{dt}}$ + 20

at P = 100 and $\frac{\textup{dP}}{\textup{dt}}$ = 10 people per month

we have

$2S\frac{\textup{dS}}{\textup{dt}}$ = 2 × 110 × 100 × 10 + 20

$2S\frac{\textup{dS}}{\textup{dt}}$ = 220020

$\frac{\textup{dS}}{\textup{dt}}$ = $\frac{\textup{220020}}{\textup{2S}}$

Change in sulfur oxide in the air = $\frac{\textup{110010}}{\textup{S}}$

8 0

2 years ago

Helppppppppppppppppppppppppp ASAP

S_A_V [24]

Answer:

4.8

Step-by-step explanation:

3 0

2 years ago

At the beginning of the day, stock XYZ opened at $6.12. At the end of the day, it closed at $6.88. What is the rate of change of

Natalija [7]

Answer:

C is the correct option.

Step-by-step explanation:

We have been given that

stock XYZ opened at $6.12 and it closed at $6.88 and we have find the rate of change of stock.

Change in the value =| Initial - final |

Change in the value = |6.12-6.88|

Change in the value = 0.76

Hence, the rate of change of stock is given by

$\frac{\text{Change in value}}{\text{initial value}}\times100\\\\=\frac{0.76}{6.12}\times100\\\\=12.4\%$

C is the correct option.

7 0

2 years ago