The time required to transmit the frame and receive the acknowledgment DIFS + 3SIFS +820μsec
<h3>
What is Bytes?</h3>
- Digital information is stored in units called bytes, which typically have eight bits.
- The byte is the lowest addressable unit of memory in various computer architectures because it was historically the amount of bits needed to encode a single character of text in a computer.
- Network protocol specifications such as The Internet Protocol (RFC 791) refer to an 8-bit byte as an octet to distinguish them from the ordinary 8-bit definition.
- Depending on the bit endianness, an octet's bits are typically counted from 0 to 7 or 7 to 0, respectively. Since the initial bit is a zero, the eighth bit is a seven.
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I hope you are trying to ask the question below:
<u>Question</u>:
Suppose an 802.11 b station is configured to always reserve the channel with the RTS/CTS sequence.
Suppose this station suddenly wants to transmit 1,000 bytes of data, and all other stations are idle at this time.
As a function of SIFS and DIFS, and ignoring propagation delay and assuming no bit errors, calculate the time required to transmit the frame and receive the acknowledgment.
False - because not every business plans work
Answer:
$20,700 ordinary loss
Explanation:
Based on the information given if the first Operating assets generated a gain of the amount of $38,700 while the second assets generated a loss of the amount of $59,400 after been sold out which indicate or means that Hugo should recognize the amount of $20,700 ORDINARY LOSS which is calculated as :
Ordinary loss =-$59,400+$38,700
Ordinary loss =-$20,700
Therefore As a result of these sales, Hugo should recognize:$20,700 ORDINARY LOSS