What is the product of 1/2x-1/4 and 5x^2-2x+6

Mathematics

1 answer:

alex41 [277]2 years ago

8 0

Answer:

$\frac{5}{2} x^{3} -\frac{9}{4}x^{2} +\frac{7}{2} x-\frac{3}{2}$

Step-by-step explanation:

$1. (\frac{1}{2} x-\frac{1}{4} )(5x^{2} -2x+6)\\\\2. \frac{1}{4}(2x-1)(5x^{2} -2x+6)\\\\3. \frac{1}{4} (10x^{3} -4x^{2} +12x-5x^{2} +2x-6)\\\\4. \frac{1}{4} (10x^{3} -9x^{2} +14x-6)\\\\5. \frac{5}{2} x^{3} -\frac{9}{4} x^{2} +\frac{7}{2} x-\frac{3}{2}$

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A triangle with sides 11m , 13m and 18m is a right triangle. A True B False

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$\bold{\huge{\pink{\underline{ Solution}}}}$

$\bold{\underline{ Given :-}}$

A triangle with sides 11m, 13m and 18m

$\bold{\underline{ To \: Find :-}}$

We have to check it whether it is right angled triangle or not?

$\bold{\underline{ Let's \: Begin :-}}$

$\sf{\red{ In \:right \:angled\ : triangle, }}$

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We imply it in the given triangle ,

$\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}$