Sent a picture of the solution to the problem (s). I usually graph at least 5 points. Usually one is 0 and I go up from zero and down from zero.
Answer:
-32+y+90
y=122
Step-by-step explanation:
Answer:
x<9
Step-by-step explanation:
Answer:
x=1 and y=4/5
Step-by-step explanation:
<u>Given system of equations</u>
3x+5y=7
5x+10y=13
<u />
<u>Multiply first equation by 2</u>
2(3x+5y)=2(7)
6x+10y=14
<u>Eliminate y-variable to get "x"</u>
6x+10y=14
<u>- 5x+10y=13</u>
x = 1
<u>Substitute x=1 into either equation and find "y"</u>
3x+5y=7
3(1)+5y=7
3+5y=7
5y=4
y=4/5
Therefore, x=1 and y=4/5
Step-by-step explanation:
Given that Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. We are to calculate the probability that Rita will need to pick atleast 5 beads before she picks a grey bead from her collection.
Prob for drawing atleast 5 beads before she picks a grey bead from her collection
= 1-Prob for drawing atleast one grey beed in the first 5 draws.
(Because these two are complementary events)
no of grey beeds drawn in first 5 trials is
Bi=(5,1/6)
Prob for drawing atleast one grey beed in the first 5 draws.
=1-Prob of no grey
Hence required prob=P(X=0 in first 5 draws)
= 0.4018
6th beeds onwards can be grey also.
Nearest answer is c)0.45
