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3 years ago

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After a lesson on exponents,Tia went home and said to her mom,"I learned that 10 to the power of 4 is the same as 40,000." She h

as made a mistake in her thinking. Use words,numbers, or a place value chart to help Tia correct her mistake.

2 answers:

White raven [17]3 years ago

6 0

Tia went home and said to her mom,"I learned that 10 to the power of 4 is the same as 40,000."

Tia made a mistake in her thinking. Exponent represents the number of zeros.

$10^4$ means we multiply 10 four times

$10^4= 10*10*10*10=10000$

For exponent 4, we put 4 zeros. So answer is 10,000.

Julli [10]3 years ago

6 0

Answer:

$10^{4}$ = 10 × 10 × 10 × 10 = 10,000

Step-by-step explanation:

After a lesson on exponents, Tia said to her mom, "I learned that 10 to the power of 4 is the same as 40,000."

In Mathematics, 10 to the power of 4,conventionally is written as $10^{4}$ which means ten multiplied by itself a certain number of times (given exponent).

She is saying $10^{4}$ that is 10 × 10 × 10 × 10 this would be equal to 10,000.

Thus, we can write

10 to the power of 4 = $10^{4}$ = 10 × 10 × 10 × 10 = 10,000

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Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

$P(A) = P_{1} + P_{2} + P_{3}$

In which $P_{1}$ is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

$P_{1} = 0.35*0.25 = 0.0875$

$P_{2}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{2} = 0.15*0.05 = 0.0075$

$P_{3}$ is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

$P_{3} = 0.50*0.15 = 0.075$

So

$P(A) = 0.0875 + 0.0075 + 0.075 = 0.17$

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

$P = \frac{0.5*0.15}{0.17} = 0.4412$

There is a 44.12% probability that the defective product came from C.

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Step-by-step explanation:

Step-by-step explanation:

From the question we are told that

Sample size 100

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Generally the upper control limit UCl is mathematically given as

Lower limit control limits:

$UCL =P_a_v_g _Z\sqrt{\frac{P_a_v_g(1-P_a_v_g) }{S} }$

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