Question

*J has coordinates of (10,-2) and n has coordinates of (-4,6) find the midpoint of jn

Answer 1

Answer:

The he coordinates of midpoint of JN are (3,2).

Step-by-step explanation:

The coordinates of J are (10,-2) and the coordinates of N are (-4,6).

The midpoint formula:

$m=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

The midpoints of JN is

$m=(\frac{10+(-4)}{2},\frac{-2+6}{2})$

$m=(\frac{6}{2},\frac{4}{2})$

$m=(3,2)$

Therefore the coordinates of midpoint of JN are (3,2).

Answer 2

The midpoint of the line JN is calculated by getting the sum of the coordinates and dividing by 2. 
                     x - coordinate = (10 + -4) / 2 = 3
                      y - coordinate = (-2 + 6) / 2 = 2

Therefore, the midpoint of line JN is equal to (3, 2).