Answer:
Step-by-step explanation:
a) Here, the first term is .48 and the common ratio is 1/100 (since each new 48 is 1/100 th of the previous 48). a
Use the formula s = sum of geometric series = -----------
1 - r
0.48 48
which in this case is s = --------------- = ------------ = 48/99 = 16/33
1 - 1/100 100 - 1
Check this result by finding 16/33 on a calculator. Is the result equal to 0.484848484848.... ? Yes
b) Here we have the bar over the 8 only. 0.48 with the bar over the 8 is equivalent to 0.4888888888 ...
0.08
or 0.4 + 0.0888888888 ... or 0.4 + ------------
1 - 1/10
0.08 8
and this simplifies to 0.4 + ------------ = 0.4 + ---------
9/10 90
Evaluating this last result on a calculator results in 0.488888888 ...
c) 0.48 expressed as a fraction is 48/100 = 12/25
240 is the correct answer.
No, it is not a valid inference because her classmates do not make up a random sample of the students in the school.
Sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
As given,
Let a-d, a, a +d be three numbers
Sum =33
⇒a-d + a +a +d =33
⇒ a =11
Sum of cubes= 5049
⇒ (a-d)³ + a +(a +d)³ =5049
⇒ a³ -d³ -3a²d +3ad² + a³ +a³ +d³ +3a²d +3ad² =5049
⇒3a³ + 6ad² = 5049
⇒ d=± 4
Therefore, sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
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Use Pythagorean Theorem
C2 = a2 + b2
c2 = 20^2 + 48^2
c2 = 400 + 2304
c2 = 2704
c = 52