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3 years ago

Can someone help me with this? please.

Mathematics

1 answer:

algol [13]3 years ago

5 0

28,000 + 3,000x = 30,000 + 2,800x
3,000x - 2,800x = 30,000 - 28,000
200x = 2,000
x = 2,000/200
x = 10....after 10 yrs, company A and company B will be the same

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Please can someone do itpleaseeeeeeee

alukav5142 [94]

Answer:

a=250

b=10

done...

3 0

2 years ago

find three consecutive integers such that the sum of twice he smallest and 3 times the largest is 126.

vladimir1956 [14]

$a,a+1,a+2\ \ -\ three\ consecutive\ integers\\\\
2a+3(a+2)=126\\\\
2a+3a+6=126\\\\
5a+6=126\ \ \ |Subtract\ 6\\\\
5a=120\ \ \ |Divide\ by\ 5\\\\
a=24\\\\Numbers\ are:\ 24,25,26.$

8 0

3 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

10 months ago

A rectangular park is 5/6 miles wide and 1. 5/6 miles long what is the area of the park enter your anwer as a mixed number in si

valina [46]

Answer: 1 19/36

multiply 5/6 by 1 5/6

6 0

3 years ago

Please can someone help please

Darya [45]

Answer:

A. 10.2

B.3 √5

3 0

3 years ago