Answer:
-x+2
Step-by-step explanation:
3x+(2−4x)
=3x+2-4x
=3x-4x+2
=-x+2
I hope this helps!
The segment addition postulate tells you that
... JK + KL = JL
a) Filling in the given information, you have
... 3n + (5n-7) = 25
... 8n = 32 . . . . . . . . . . . collect terms, add 7
... n = 4 . . . . . . . . . . . . . divide by 8
b) Now, you know that
... JK = 3n = 3·4 = 12
... KL = 5n-7 = 5·4-7 = 13
The segments are: JK = 12; KL = 13.
Answer: C) All real values of x such that ![x \le 0](https://tex.z-dn.net/?f=x%20%5Cle%200)
In other words, x must be 0 or smaller.
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Explanation:
The reason why is because we must make the stuff under the square root to never be negative. We must make -2x be 0 or larger.
So,
![-2x \ge 0 \\\\-2x+2x \ge 0+2x \ \text{ ... add 2x to both sides}\\\\0 \ge 2x\\\\2x \le 0 \ \text{ ... flip both sides, and the inequality sign}\\\\x \le 0/2 \ \text{ ... divide both sides by 2}\\\\x \le 0](https://tex.z-dn.net/?f=-2x%20%5Cge%200%20%5C%5C%5C%5C-2x%2B2x%20%5Cge%200%2B2x%20%5C%20%5Ctext%7B%20...%20add%202x%20to%20both%20sides%7D%5C%5C%5C%5C0%20%5Cge%202x%5C%5C%5C%5C2x%20%5Cle%200%20%20%5C%20%5Ctext%7B%20...%20flip%20both%20sides%2C%20and%20the%20inequality%20sign%7D%5C%5C%5C%5Cx%20%5Cle%200%2F2%20%20%5C%20%5Ctext%7B%20...%20divide%20both%20sides%20by%202%7D%5C%5C%5C%5Cx%20%5Cle%200)
As an example, if x = -2, then -2x = -2(-2) = 4 is positive. Applying the square root to a positive number is valid.
But if x = 5, then -2x = -2*5 = -10 is under the square root, which is not allowed.
Since there is a 4 on the outside of the radical and we're taking a cube root, you can work backwards and do 4^3 = 64
Letter D