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Rudik [331]
3 years ago
13

Claim: most adults would erase all of their personal information online if they could. A software firm survey of 651 randomly se

lected adults showed that 64% of them would erase all of their personal information online if they could. Find the value of the test statistic.
the value of the test statistic is:
Mathematics
1 answer:
Bess [88]3 years ago
7 0

Answer:RTGrg

Step-by-step explanation:just need points lol sorry

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The best answer will be marked brainliest!!!!!!!!!!!!!!!
Colt1911 [192]

Answer:

c and d

Step-by-step explanation:

5 0
3 years ago
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I know it’s a lot to ask but please show your work so I know how to do it. Thank you!
jonny [76]

Answer:

The answer to your question is below

Step-by-step explanation:

Use trigonometric functions to find x

13.  cos 40 = 5/x

     x = 5 / cos 40

     x = 5 / 0.766

     x = 6.5

14. tan 25 = x/9

     x = 9tan 25

     x = 9(0.466)

     x = 4.2

15.- cos 65 = x/12

      x = 12 cos 65

      x = 12 (0.423)

      x = 5.1

16.- sin 32 = 15/x

      x = 15 / sin 32

      x = 15 / 0.53

      x = 28.3

17.- tan 55 = 20 / x

      x = 20 / tan 55

      x = 20 / 1.42

      x = 14

18.- sin31 = x / 18

     x = 18 sin 31

     x = 18 (0.52)

     x = 9.3

8 0
3 years ago
One of the earliest applications of the Poisson distribution was in analyzing incoming calls to a telephone switchboard. Analyst
grandymaker [24]

Answer:

(a) P (X = 0) = 0.0498.

(b) P (X > 5) = 0.084.

(c) P (X = 3) = 0.09.

(d) P (X ≤ 1) = 0.5578

Step-by-step explanation:

Let <em>X</em> = number of telephone calls.

The average number of calls per minute is, <em>λ</em> = 3.0.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.0.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...

(a)

Compute the probability of <em>X</em> = 0 as follows:

P(X=0)=\frac{e^{-3}3^{0}}{0!}=\frac{0.0498\times1}{1}=0.0498

Thus, the  probability that there will be no calls during a one-minute interval is 0.0498.

(b)

If the operator is unable to handle the calls in any given minute, then this implies that the operator receives more than 5 calls in a minute.

Compute the probability of <em>X</em> > 5  as follows:

P (X > 5) = 1 - P (X ≤ 5)

              =1-\sum\limits^{5}_{x=0} { \frac{e^{-3}3^{x}}{x!}} \,\\=1-(0.0498+0.1494+0.2240+0.2240+0.1680+0.1008)\\=1-0.9160\\=0.084

Thus, the probability that the operator will be unable to handle the calls in any one-minute period is 0.084.

(c)

The average number of calls in two minutes is, 2 × 3 = 6.

Compute the value of <em>X</em> = 3 as follows:

<em> </em>P(X=3)=\frac{e^{-6}6^{3}}{3!}=\frac{0.0025\times216}{6}=0.09<em />

Thus, the probability that exactly three calls will arrive in a two-minute interval is 0.09.

(d)

The average number of calls in 30 seconds is, 3 ÷ 2 = 1.5.

Compute the probability of <em>X</em> ≤ 1 as follows:

P (X ≤ 1 ) = P (X = 0) + P (X = 1)

             =\frac{e^{-1.5}1.5^{0}}{0!}+\frac{e^{-1.5}1.5^{1}}{1!}\\=0.2231+0.3347\\=0.5578

Thus, the probability that one or fewer calls will arrive in a 30-second interval is 0.5578.

5 0
3 years ago
A pan for baking French bread is shaped like half a cylinder. It is 12 inches long and 3.5 inches in diameter. What is the volum
Lerok [7]

Step-by-step explanation:

5 0
3 years ago
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5u − –20u − u − 18u + –11u = 10<br> HURRRY PLEEEEESEEEE I ONLY HAVE 4 minutes left
drek231 [11]
5u - (-20u) - u - 18u + (-11u) = 10
5u + 20u - u - 18u - 11u = 10
-5u = 10
-5(-2) = 10

So, in conclusion, X, is equal to -2.
8 0
3 years ago
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