Answer:
Step-by-step explanation:
Reduction to normal from using lambda-reduction:
The given lambda - calculus terms is, (λf. λx. f (f x)) (λy. Y * 3) 2
For the term, (λy. Y * 3) 2, we can substitute the value to the function.
Therefore, applying beta- reduction on "(λy. Y * 3) 2" will return 2*3= 6
So the term becomes,(λf. λx. f (f x)) 6
The first term, (λf. λx. f (f x)) takes a function and an argument, and substitute the argument in the function.
Here it is given that it is possible to substitute the resulting multiplication in the result.
Therefore by applying next level beta - reduction, the term becomes f(f(f(6)) (f x)) which is in normal form.
Answer:
perimeter: 26
area: 16 + 10 =26
perimeter: add all lengths.
area: multiply LxW
800 the strategy I used was adding 32 over and over 25 times
<h2>
Hello!</h2>
The answer is:
The answer is the fourth option,

<h2>
Why?</h2>
Piecewise functions are functions that are composed by two or more expressions, the expression to use will depend of the domain or input that we need to evaluate.
We are given the piecewise function:

There, we know that:
We should use the first expression if the value to evaluate is less than -2.
So, for this case, the function will be:

We should use the second expression if the value to evaluate is greater or equal than 2.
So, for this case, the function will be:

Now, since we are given that the value to evaluate is -3, and its less than -2, we need to use the first expression, and evaluate it.

So, evaluating the function we have:



Hence, we have that the answer is the fourth option,

Have a nice day!
Answer:
steps below
Step-by-step explanation:
x-a=0
x=a plug in xⁿ - aⁿ
xⁿ - aⁿ = aⁿ - aⁿ = 0
(x-a) must be a factor of xⁿ - aⁿ