Given a sequence; a₁,a₂,a₃...,an,
The common difference is d= a₂-a₁=a₃-a₂=a₄-a₃....
In this case:
a₁=1.05
a₂=1.1
d=a₂-a₁=(1.1)-(1.05)=0.05
Answer: The common difference is 0.05.
1) Initial fall => 46 yards
2) First bounce = > rising 46/2 yards and falling the same => 23*2 = 46
3) Second bounce => rising 23/2 yards and falling the same => 11.5*2 = 23
4) Third bounce => rising 11.5/2 yards and falling the same => 5.75 * 2 = 11.5
5) Fourth bounce => rising 5.75 / 2 yards = 2.875
Sum = 46 + 46 + 23 + 11.5 + 2.875 = 129.375
Answer: 129.375 yd
Answer:
Step-by-step explanation:
I multiplied 5% and 1150 dollars and that got me 1207.5
3 because
2n+3(n-4)+5=5n-7
2n+3n-12+5=5n-7
5n-7=5n-7
5n-5n=7-7
0
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