The production would be a my a point inside the curve. The curve shows the possibility of producing with all possible materials so inside the curve is representative of one or more of the resources not being used to its full capacity.
Answer:
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Answer:
p = 59.11 dollars
Explanation:
Given
Price: p(x) = 8eˣ (0 ≤ x ≤ 2)
Revenue; R = x*p = 8xeˣ
p = ? when R be at maximum
We can apply
dR/dx = d(x*p)/dx = 0
⇒ d(8xeˣ)/dx = 8*(1*eˣ + x*eˣ) = 0
⇒ eˣ*(1 + x) = 0 ⇒ x = - 1
as x = - 1 ∉ [0, 2]
then, we have
p(0) = 8e⁰ = 8
R = 0*8 = 0
If x = 1
p(1) = 8e¹ ≈ 21.74
R = 1*21.74 = 21.74
If x = 2
p(2) = 8e² ≈ 59.11
R = 2*59.11 = 118.22
Implies that, R(x) is maximum at x = 2.
Thus, the price that maximize the revenue of the company is 59.11 dollars.
Answer: b. 233,500
Explanation:
The expected cashflow is;
= (EBIT * (1 - tax) ) + Depreciation - change in net working capital - capital expenditure
= (270,000 * (1 - 25%)) + 85,000 - 19,000 - 35,000
= $233,500
