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e-lub [12.9K]
3 years ago
8

Find the value of n?

Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0

Answer:

n=q^2

Step-by-step explanation:

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Solve 12x + 6 2 9x + 12.<br> A. X2<br> B. xs2<br> O<br> C. X26<br> 0<br> D. Xs6<br> SUBNANT
Alexxx [7]

Answer:

269

Step-by-step explanation:

Solve 12x + 6 2 9x + 12.

A. X2

B. xs2

O

C. X26

0

D. Xs6

8 0
3 years ago
the values of x and y vary diectly and one pair of values are given write an equation that relates x and y if x=-5 and y=10
ki77a [65]

Answer:

2x = -y

Step-by-step explanation:

4 0
4 years ago
A number is 9 more than another number. Twice the sum of the two numbers is 10. Find the two numbers.
Brrunno [24]

Step-by-step explanation:

the formula can be;

X+9x=10

10x=10X=10/10=1

X=1+9(1)=1+9=10 Answer

4 0
3 years ago
SIX LESS THAN TWICE A NUMBER, X, IS 38 WHAT IS THE VALUE OF X
stealth61 [152]

Answer:

17

Step-by-step explanation:

first write the equation:

twice a number x is 2x

six less is -6

so equation is 2x - 6 = 38

solve for x:

2x = 34

x = 17

6 0
3 years ago
Read 2 more answers
Discrete mathematics (Show your work)
UkoKoshka [18]

Answer:

  110011

Step-by-step explanation:

The tedious way to do this is to divide by 2 until the quotient is 0, noting remainders at each step:

  • 51/2 = 25 r 1
  • 25/2 = 12 r 1
  • 12/2 = 6 r 0
  • 6/2 = 3 r 0
  • 3/2 = 1 r 1
  • 1/2 = 0 r 1

Taken from bottom to top, the list of remainders comprises the binary number: 110011.

___

Alternatively, you can convert the number to hexadecimal (base-16) or octal (base-8), then make the simple conversions from those digits to binary. In octal, we have ...

  • 51/8 = 6 r 3
  • 6/8 = 0 r 6

Then the number in octal is 51 = 63₈. Your familiarity with binary lets you write the binary number from memory, since you recall 6 = 110₂ and 3 = 011₂. Each octal digit must be expressed as three binary digits (or bits) in order to maintain appropriate place values.

That is, ...

  63₈ = 110011₂

_____

<em>Comment on octal-binary conversion</em>

The binary values of the digits 0-7 are ...

  • 0 = 000₂
  • 1 = 001₂
  • 2 = 010₂
  • 3 = 011₂
  • 4 = 110₂
  • 5 = 101₂
  • 6 = 110₂
  • 7 = 111₂

Three binary bits can express numbers 0-7 as shown. So, using octal as an intermediate base in doing the conversion to binary lets you do the conversion 3 bits at a time, instead of one bit at a time.

Likewise, four binary bits can express numbers 0-15, so hexadecimal as an intermediate base lets you do the conversion 4 bits at a time: 51/16 = 3 r 3 ⇒ 0011 0011₂.

8 0
4 years ago
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