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168=n+(n+2)+(n+4)
168=3n +6
168 - 6 = 3n
162/3=n
54=n
integer 1: 54
integer 2=n+2=56
integer 3=n+4=58
This is the concept of probability, we are required to calculate for the probability of rolling a 4 with a single die four times in a row;
To solve this we proceed as follows;
The probability space of a die is x={1,2,3,4,5,6}
The probability of a die falling on any of this number is:
P(x)=1/6
Thus the probability of rolling a 4 with a single die four times which makes up mutually exclusive events will be:
1/6*1/6*1/6*1/6
=(1/6)^4
=1/1296
The answer is B] 1/1296
Answer:
x1 = 275 miles (shorter)
x2 = 318 miles (longer)
Step-by-step explanation:
Let
x1 = be the shorter route
v1 = speed of the car in the shorter route
t1 = time it took to cover shorter route
x2 = the longer route
v2 = speed of the car in the longer route
t2 = time it took to cover longer route
x1 + 43 = x2 (1)
v2 = v1 -2 (2)
v2 = x2/t2 = x2/6
v1 = x1/t1 = x1/5
This means that
v2 = v1 -2 =>
x2/6 = x1/5 -2
The system of equations results
a. x1 -x2 = -43
b. x1/5 - x2/6 = 2
Solving this system of equations, we find that
x1 = 275 miles
x2 = 318 miles
