All categories

2 years ago

Math class, need help on this. Anybody??

Mathematics

1 answer:

ASHA 777 [7]2 years ago

3 0

Answer:

y = 2x-5

Step-by-step explanation:

y = 2x+2

We know the slope of this line is 2 because it is in the form y =mx +b where m is the slope

We want a parallel line so it has the same slope

We can use the point slope form of the equation

y-y1 = m(x-x1)

y--1 = 2(x-2)

y+1 = 2(x-2)

Distribute

y+1 = 2x-4

Subtract 1 from each side

y+1-1 = 2x-4-1

y = 2x-5

This is in slope intercept form

You might be interested in

plz help me suzy spent 6 7/8 days working on her English paper 3 1/6 days on her science project and 1 1/2 days studying for her

malfutka [58]

Answer:

English time + Math Time = 6 7/8 + 1 4/8 = 7 7/8+4/8 = 8 3/8

8 3/8 - Science time = difference = 8 3/8- 3 1/6 = 5 5/24

She spent 5 5/24 days more on her English and Math test than Science

Step-by-step explanation:

5 0

3 years ago

I need help with this question

dsp73

The slope is 9/3 which can be simplified into 3/1

5 0

1 year ago

Stan drove for h hours at a constant rate of r miles per hour. How many miles did he cover during the final 20 minutes of his dr

valentinak56 [21]

r multiplied by 1/5h

6 0

2 years ago

Read 2 more answers

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

2 years ago

From 1960 to 1970, the consumer price index (CPI) increased from 29.6 to 38.8. If a macaroni and cheese dinner cost $0.37 in 196

ohaa [14]

<span>im pretty sure its C $0.12

best of luck hope i helped :)
</span>

3 0

3 years ago

Read 2 more answers

Math class, need help on this. Anybody?? ​

Math class, need help on this. Anybody??