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velikii [3]
4 years ago
13

Henry is having a problem with the electrical system on his current laptop. The battery for the laptop will not charge. Henry to

ok the AC adapter and battery from another laptop that is known to work, and put them in his current laptop, but still the battery will not charge.
Computers and Technology
1 answer:
Juliette [100K]4 years ago
4 0

Answer:

There is a short circuit in a component in the power circuit.

Explanation:

The power circuit in a computer system, regulates, rectifies and steps down power and voltage entering the main motherboard.

When a power surge capable of damaging the motherboard occurs, A component in the power circuit is shorted, not allowing the dangerous power to pass.

This can be troubleshooted by passing a high current, since the shorted component has a high emf. It over heats and is detected and changed.

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Question 5 (2 points)
Scrat [10]

Answer:

B) 5 m/s

Explanation:

Took the test and this was the correct answer :)

6 0
3 years ago
Find the greatest common factor of 48 and 36.​
gregori [183]

Answer:

Hello, The prime factorization of 48 is: 2 x 2 x 2 x 2 x 3. And The  prime factorization of 36 is: 2 x 2 x 3 x 3.

Explanation:

The prime factors and multiplicities 48 and 36 have in common are: 2 x 2 x 3.

2 x 2 x 3 is the "GCF" of 48 and 36.

"GCF"(48,36) = 12.

7 0
3 years ago
Companies use virtualization to do all of the following except:
dangina [55]

Answer:

c)

Explanation:

Virtualization refers to running a virtual instance of a computer system apart from the actual software. Companies use this virtualization to do all of the following except Reduce the amount of applications in corporate datacenters. Instead few systems have the applications and those systems are cloned through virtualization.

4 0
3 years ago
Write a program to simulate the design process of the course. First, create a struct for the course which consists of following
Dmitry [639]

Answer:

#include <iostream>

using namespace std;

struct Course

{

int courseNumber;

int courseStartDate;

int courseHours;

int lecturerId;

};

struct Lecturer

{

int lecturerId;

int officeHours;

Course courseTeaching[2];

};

struct Student

{

int studentId;

Course coursesTaken[2];

};

int main()

{

Course courseObj1, courseObj2, courseObj3;

courseObj1.courseNumber = 1000;

courseObj1.courseStartDate = 20200107;

courseObj1.courseHours = 2;

courseObj1.lecturerId = 100;

courseObj2.courseNumber = 1100;  

courseObj2.courseStartDate = 20200113;

courseObj2.courseHours = 4;

courseObj2.lecturerId = 200;

courseObj3.courseNumber = 1200;

courseObj3.courseStartDate = 20200203;

courseObj3.courseHours = 4;

courseObj3.lecturerId = 100;

Lecturer lecturerObj1, lecturerObj2;

lecturerObj1.lecturerId = 100;

lecturerObj1.officeHours = 2;

lecturerObj1.courseTeaching[0] = courseObj1;

lecturerObj1.courseTeaching[1] = courseObj3;

lecturerObj2.lecturerId = 200;

lecturerObj2.officeHours = 2;

lecturerObj2.courseTeaching[0] = courseObj2;

Student student;

student.studentId = 2000;

student.coursesTaken[0] = courseObj1;

student.coursesTaken[1] = courseObj3;

cout << "1. Lecturer ID: " << lecturerObj1.lecturerId << "\tOffice Hours: " << lecturerObj1.officeHours << endl;

for(int i = 0; i < 2; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj1.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj1.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj1.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj1.courseTeaching[i].lecturerId << endl;

cout << "\n2. Lecturer ID: " << lecturerObj2.lecturerId << "\tOffice Hours: " << lecturerObj2.officeHours << endl;

for(int i = 0; i < 1; i++)

cout << "COURSE " << (i + 1) << ":\n---------\n" << "Course Number: " << lecturerObj2.courseTeaching[i].courseNumber << endl << "Course start date: " << lecturerObj2.courseTeaching[i].courseStartDate << endl << "Course hours: " << lecturerObj2.courseTeaching[i].courseHours << endl << "Lecturer ID: " << lecturerObj2.courseTeaching[i].lecturerId << endl;

int courseNumber;

cout << "\n Enter the course number: ";

cin >> courseNumber;

int index = -1;

int len = sizeof(student.coursesTaken) / sizeof(student.coursesTaken[0]);

int totalHours = 0;

for(int i = 0; i < len; i++)

{

if(student.coursesTaken[i].courseNumber == courseNumber)

{

totalHours += student.coursesTaken[i].courseHours;

}

}

if(totalHours == 0)

cout << "\n Student is not registered to this course!\n";

else

cout << "\nStudent " << student.studentId << " needs " << totalHours << " hours per week of this course.\n";

return 0;

}

Explanation:

  • Create the 3 objects of Course class and set their properties respectively.
  • Create the 2 objects of Lecturer class and set their properties respectively.
  • Create an object of Student class and set their properties respectively.
  • Run a for loop and check whether the current courseNumber is already added and then increment the total number of hours for that course.
  • Finally check if totalHours is equal to 0 or not and then display the suitable message accordingly.
4 0
4 years ago
The ____ loop can be used to process each element of an array.?
salantis [7]
The "For each" loop can be used to process each element of an array.?
4 0
3 years ago
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