1) Let x be the original speed that he was driving;
x mph ---> 1.5 hours
x+44 mph --> 2.5 hours
1.5x + 2.5(x+44)=206
1.5x+2.5x+110=206
4x=206-110
4x=96
x=24
Therefore, he was travelling at 24 mph in the fog.
2) Let x be the speed of 1 snail,
The other snail travels at the speed of x+1 cm/min
23x+23(x+1)=391 <-- solve for x
23x+23x+23=391
46x=368
x=368/46
x=8
Therefore one of the snail travels at 8 cm/min while the other goes at 9 cm/min
7) Let x be one crew
Then the other crew would be working at x+0.5
3.2x+3.2(x0.5)=8 <-- solve for x
3.2x+1.6x=8
4.8x=8
x=8/4.8
x=1.6666 or 1.7 miles
Therefore, one of the crew does 1.7 miles per day and the other crew does (0.5*1.7)=0.85 miles
Hope I helped :)
Answer:
x=4
Step-by-step explanation:
Answer:
Step-by-step explanation:
T is at (1,2)
where x = 1 and y = 2
so if it's reflected over the x axis then it moves down wards. to (1, -2)
Part A:
f(x)=30(1.2)^x
f(x)=45+3x
Part B: Neighborhood A is 74.6496, so that rounds to 75 homes, and Neighborhood C is exactly 60 homes
Part C:
i would graph them in a graphing calculator, and use the functions to see where the 2 lines intersect.
The x value for when they intersect (# of years) is 3.3207883, so approx. 3.3 years for them to be equal
