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Annette [7]
2 years ago
11

1+1000000000000000000000

Mathematics
2 answers:
BabaBlast [244]2 years ago
5 0

Answer:

1000000000000000000001

Step-by-step explanation:

1000000000000000000000

+                                               1

------------------------------------------------

1000000000000000000001

solniwko [45]2 years ago
4 0

Answer:

1000000000000000000001

Step-by-step explanation:

Done. You're welcome

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Evaluate expression 15/x for x=3
irga5000 [103]

Answer:

x=5

Step-by-step explanation:

15÷5=3

that is the right answer

4 0
2 years ago
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Helppppppppppppppopo
Vesna [10]
The answer is A, all that was needed was to do the math.

8 0
3 years ago
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OMG PLS HELP ME!!!!!! I NEED THIS ASAP!!! 100 PTS!!!!!!!<br><br> (its in the pic)
Rainbow [258]

By algebra properties we find the following relationships between each pair of algebraic expressions:

  1. First equation: Case 4
  2. Second equation: Case 1
  3. Third equation: Case 2
  4. Fourth equation: Case 5
  5. Fifth equation: Case 3

<h3>How to determine pairs of equivalent equations</h3>

In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:

First equation

(7 - 2 · x) + (3 · x - 11)

(7 - 11) + (- 2 · x + 3 · x)

- 4 + (- 2 + 3) · x

- 4 + (1) · x

- 4 + (5 - 4) · x

- 4 - 4 · x + 5 · x

- 4 · (x + 1) + 5 · x → Case 4

Second equation

- 7 + 6 · x - 4 · x + 3

(6 · x - 4 · x) + (- 7 + 3)

(6 - 4) · x - 4

2 · x - 4

2 · (x - 2) → Case 1

Third equation

9 · x - 2 · (3 · x - 3)

9 · x - 6 · x + 6

3 · x + 6

(2 + 1) · x + (14 - 8)

[1 - (- 2)] · x + (14 - 8)

(x + 14) - (8 - 2 · x) → Case 2

Fourth equation

- 3 · x + 6 + 4 · x

x + 6

(5 - 4) · x + (7 - 1)

(7 + 5 · x) + (- 4 · x - 1) → Case 5

Fifth equation

- 2 · x + 9 + 5 · x  + 6

3 · x + 15

3 · (x + 5) → Case 3

To learn more on algebraic equations: brainly.com/question/24875240

#SPJ1

5 0
1 year ago
Can someone please help me please
Assoli18 [71]
A
Volume of the Cylinder
Givens
H = 60 yards.
Diameter = 20 yards
pi = 3.14

Formula
V = pi * r^2 * h

Calculations
r = d/2
r = 32/2
r = 16

V =  3.14 * 16^2 * 60 
V = 48230 cubic yards [Cylinder's Volume]

Cone
<em>Formula</em> 
V = 1/3 pi r^2 H

<em>Givens</em>
pi = 3.14
r = 16 yards
h = 20 yards

<em>Sub and solve</em>
V = 1/3 3.14 * 16^2 * 20
V = 5359 cubic yards.

<em>Total Volume of the structure</em>
48230 + 5359 = 53589 Cubic Yards

<em>Water Content</em>
The answer to this part requires a proportion.

1 Cubic yard will hold 201.97 gallons.
53589 yd^3 = x

1/201.97 = 53589 /x  [ You should get a pretty big answer]
x = 201.87 * 53589
x = 10 819 092 gallons can be held by the tank. 

10 819 092 gallons <<<< answer

B 
If the height of both the cylinder and the cone remain the same. If the radius doubles in both the cylinder and the cone then the tank will hold 4 times as much. 

Total volume before doubling the radius = pi * r^2 h + 1/3 pi r^2 h
New Total Volume = pi * (2*r)^2 h + 1/3 pi * (2r)^2 h
New Total volume = pi * 4r^2 h + 1/3 pi *4 r^2 h
New Total Volume = 4 [pi r^2 h + 1/3 pi r^2 h]
but pi r^2 h + 1/3 pi r^2 h is the total volume before doubling the radius

New volume = 4 original volume. <<<<< answer to part B
6 0
3 years ago
A bag contains 3 triangles, 4 squares, 5 pentagons, and 6 hexagons. If one shape is randomly chosen, what is the probability tha
e-lub [12.9K]

I’d say that it’s definitely random choice for the squares, pentagons, and hexagons. But, if we are looking at how common it would be between the 3 of them, then I would say that it would be one of the hexagons, because there are more hexagons than any of the other shapes in the bag.

3 0
3 years ago
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