Answer:
1/2
Step-by-step explanation:
Slope is rise over run. So you will want to pick 2 points that cross an intersection rise to the upper ones lone, and then run to the point, while counting. I hope this helps :)
- I started at the point (2,0) ran up 1, and then ran over 2 to (0,1).
Answer:
Yes
Step-by-step explanation:
We have two properties for our question :
(4, 27)
y = 3x + 15
We are being asked whether the point (4, 27) is a solution of y = 3x + 15
So how do we figure this out? Well, what we have to know first that (4, 27) represents a variable, 4 which is the run on the graph, represents x in a solution. And 27 which is the rise on the graph, represents y in the solution. So when asking for a solution with two points, all we must do is substitute x and y for the two coordinates.
y = 3x + 15
y = 27 and x = 4
27 = 3(4) + 15
27 = 12 + 15
27 = 27
Since this equation is true with the respected variables, therefore signifies that (4,27) is a solution of y = 3x + 15
Undefined. That equation is the y axis and therefore intercepts the y axis at every point
The conjecture is False. A,B,C are in one plane, D is above the plane, therefore the points are not coplanar.
The statement doesn't specify where the points are.
