<h3>
Answer:</h3>
- hole: x = -4
- vertical asymptote: x = 1
- horizontal asymptote: y = -1
<h3>
Step-by-step explanation:</h3>
The function factors as ...
... f(x) = -(x+3)(x+4)/((x-1)(x+4)) = -(x+3)/(x-1) . . . . x ≠ -4
and the quotient is ...
... f(x) = -(1 +4/(x-1))
... f(x) = -1 -4/(x-1) . . . . . x ≠ -4
This has a hole at x = -4 (where the denominator factor cancels the numerator factor), a vertical asymptote at x=1 (where the denominator is zero), and a horizontal asymptote at y = -1 (the value of the function for large values of x).
f(-4) = 3(-4)^2 - 2(-4)
f(-4) = 3(16) + 8
f(-4) = 48 + 8
f(-4) = 56
I think the answer is 56 :)
Please give BRAINIEST :)
Answer:
Step-by-step explanation:
I just finished this homework so
u have
-2 -8 -18 -32 -50
-2 to -8=-6
-8 to -18=-10
-18 to -32=-14
-32 to -50=-18 now the gaps are going by 4 so it will be n^2-4
Answer:Since the integers are closed under addition, . m C n C 1/ is an integer, and hence the last equation shows that x C y is even. Therefore, we Page 3 Appendix C. Answers for Exercises 539 have proven that if x and y are odd integers, then x C y is an even integer. P1 There exists an integer k m D 2k.
Step-by-step explanation: