Complete Question
An F5 tornado is classified as having mean wind speeds greater than 261 mph. In an effort to classify a recent tornado, 20 wind speed measurements were randomly selected from within the path of the tornado. Suppose the mean wind speed for this tornado really is greater than 261 mph with a sample standard Deviation 41.09 mph. Based on the data, if we fined little to no evidence against the null hypothesis that the mean wind speed is 261 mph, we have made _______________.
Answer:
Step-by-step explanation:
From the question we are told that:
Sample size 
Population mean 
Sample mean 
Sample standard deviation 
Generally the equation t test statistics is mathematically given by
Therefore
Pvalue from table is
ANSWER:
Does not have enough information
WHY:
Because it is a bunch of i
The line n intersects line m and at the point of intersection two angles are formed, which are 3x and x.
Please note that angles on a straight line equals 180 degrees. That means angle 3x and angle x both sum up to 180. This can be expressed as;
3x + x = 180
4x = 180
Divide both sides of the equation by 4 (to eliminate the 4 on the left hand side and isolate the x)
x = 45
Read the instructions, seeding rate varies with type of grass, from 1 lb (Kentucky blue) to 3 lb/1000 sq.ft.
But please post in correct category next time.
Answer:
- 6. See solution
- 7. k = 2, k = -6
Step-by-step explanation:
6.
<u>Given equation:</u>
- The sum of the roots is q1 and the product of the roots is q2
Need to show that q1+q2 = 0
<h3>Solution</h3>
<u>Bringing the equation into standard form of ax² + bx + c = 0:</u>
- 2(x + 2)² + p(x + 1) = 0
- 2x² + 8x + 8 + px + p = 0
- 2x² + (p + 8)x + (p + 8) = 0
<u>Sum of the roots: </u>
<u>Product of the roots:</u>
<u>We see that q1 and q2 are opposite numbers, therefore their sum equals zero:</u>
- q1 + q2 = -(p + 8)/2 + (p + 8)/2 = 0
=============================================
7.
<u>Given quadratic equation:</u>
Need to find the possible values of k
<h3>Solution</h3>
<u>When the quadratic equation has equal roots, then its discriminant is equal to zero:</u>
- D = 0
- √b² - 4ac = 0
- √(-k -2)² - 4*1*4 = 0
- √k² + 4k + 4 - 16 = 0
- √k² + 4k - 12 = 0
- k² + 4k - 12 = 0
- k = {-4 ± √4² -4*1*(-12)}/2
- k = (-4 ± √16 + 48)/2
- k = (-4±√64)/2
- k = -2 ± 4
- k = 2, k = -6
