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3 years ago

How do you subtract nega

Mathematics

2 answers:

Gre4nikov [31]3 years ago

6 0

Answer:

well think of it like this. lets say your teacher made you do this problem -48 - 10. I would just act like 48 is not an negative and add 10. After that I would put the negative back. So the answer would be -58

Step-by-step explanation:

sergey [27]3 years ago

3 0

Well think of it like this. lets say your teacher made you do this problem -48 - 10. I would just act like 48 is not an negative and add 10. After that I would put the negative back. So the answer would be -58. :P

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-3 ≤ 6 <br> add 8 to both sides

yawa3891 [41]

Answer:

-3=5

6=14

so it would be 6

Step-by-step explanation:

8 0

2 years ago

From the diagram below, if the sides AD = 3 and DC = 27, and BD = X + 3, find x.

Colt1911 [192]

Given:

• AD = 3

• DC = 27

• BD = x + 3

Let's solve for x.

To solve for x, apply the altitude formula:

$\frac{AD}{BD}=\frac{BD}{DC}$

Where BD is the altitude.

Cross multiply:

$BD^2=AD*DC$

Plug in the values and solve for x:

$\begin{gathered} (x+3)^2=3*27 \\ \\ (x+3)^2=81 \end{gathered}$

Take the square root of both sides:

$\begin{gathered} \sqrt{(x+3)^2}=\sqrt{81} \\ \\ x+3=9 \\ \\ \text{ Subtract 3 from both sides:} \\ x+3-3=9-3 \\ \\ x=6 \end{gathered}$

Therefore, the value of x is 6 .

ANSWER:

d. 6

4 0

1 year ago

PLEASE HELP I’LL GIVE BRAINLIST.

kolezko [41]

Answer:

2/6 is probably your answer

Step-by-step explanation:

5 0

3 years ago

Sid brought $200 to the amusement park . the cost of admission is $16.25 , and the cost of a lunch is $6.50 . After Sid purchase

ra1l [238]

Let x represent the # of people in sid’s group: 200 - (16.25x + 6.50x) = 18.25
200 - 22.75x = 18.25
-22.75x = -181.75
x = about 8

if Sid is not included in the group, i think the answer is D. 7, but im not sure

5 0

3 years ago

For which intervals the graphs of the functions f(x) = x^3 + x^2 - 4x - 4 is positive

Nookie1986 [14]

Step-by-step explanation:

Consider a function

(

)

which is twice differentiable. The graph of such a function will be concave upwards in the intervals where the second derivative is positive and the graph will be concave downwards in the intervals where the second derivative is negative. To find these intervals we need to find the inflection points i.e. the x-values where the second derivative is 0.

5 0

3 years ago