Combine like terms by adding their FACES (Coefficients)
1) 4c² - 4
2) 20m^4 + 6m
3) -6a³ - 19a² + 8a - 10
4) -10a² - 2b + 3ab³ + 4a²b² -5b^4 - 9a²b² - 12a³b + 15ab³ = -10a² - 2b + 18ab³ - 5a²b² - 12a³b - 5b^4
5) 5a³ - 5a²
Hello!
To do this, we know the two triangles are similar, so we can set up a proportion, and then find the length of the lake.
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The two triangles (Triangle AEB and ADC) are similar. We know this because all the angles have the same measurement - They all share angle A, they both have a right angle, and therefore, their third angle measures the same.
What we know about both triangles is their hypotenuse length. We know that triangle AEB has a hypotenuse that measures 320 m, and ADC has a hypotenuse that measures 320 + 162, or 482 m.
320 : 482 is therefore the ratio between the side lengths of two triangles (AEB : ADC). We can simplify this to 160 : 241.
Now, what we are looking for is the side length DC. The corresponding side to this in triangle AEB is EB, and we know it measures 40 m. Therefore, using the ratio, we can find the measure of DC.
160 / 4 : 241 / 4
40 : 60.25
Therefore, the measure of DC is 60.25 m.
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Hope this helps!
Answer:
no
Step-by-step explanation:
We want to compare the pot holder hole dimension to the pot dimension. The hole diameter is the overall pot holder diameter less the wall thickness on either side:
hole diameter = (20 1/5) -2(1 2/7) = 20 -2(1) +1/5 -(2)(2/7)
= 18 +(1/5 -4/7) = 18 +(7 -20)/35 = 18 -13/35
= 17 22/35 . . . . cm
We want to compare this to 17 4/5. We can do that by using a common denominator for the fractions.
17 4/5 = 17 + (4/5)(7/7) = 17 28/35 . . . . cm
The pot has a diameter of 17 28/35 cm; the pot holder has a hole diameter of 17 22/35 cm, so <em>the hole is smaller than the pot</em>.
The pot will not fit into the plant pot holder.
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You can use your calculator to find the free space around the pot by computing ...
20 1/5 -2(1 2/7) -17 4/5 = free space = -6/35 . . . . cm
Negative space means the pot is larger than the hole.
Subtract k from both sides of problem
X+k-k = w+v-k
X= w+v-k
