Question

Hello can you please help me posted picture of question

Answer 1

Vertex of a parabola exists at:

$( \frac{-b}{2a},y( \frac{-b}{2a}))$

b = coefficient of x term = -4
a = coefficient of squared term = 1

So,

$\frac{-b}{2a}= \frac{4}{2}=2$

and

$y(2)=(2)^{2}-4(2)+1=-3$

Therefore, the vertex occurs at (2, -3)

Thus the correct answer is option D