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3 years ago

The ratio of bikes to helmets is 7:6 if there are 28 bikes how many helmets are there

2 answers:

6 0

Since the ratio of bikes to helmets is 7:6 the bikes are represented as 7 and helmets as 6 so just multiply the helmets by 4 and you get 28:24

otez555 [7]3 years ago

4 0

28 divided by 7 is 4 6 x 4 is 24
24 helmets

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Acute △ABC with angles α, β, and γ is inscribed in a circle. Tangents to the circle at points A, B, and C intersect in points M,

SOVA2 [1]

Answer:

The measures of angles of triangle MNP are

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the measure of arcs AB, BC and AC

we know that

The inscribed angle is half that of the arc it comprises.

$\gamma=\frac{1}{2}[arc\ AB] ----> arc\ AB=2\gamma\\\alpha=\frac{1}{2}[arc\ BC] ----> arc\ BC=2\alpha\\\beta=\frac{1}{2}[arc\ AC] ----> arc\ AC=2\beta$

step 2

Find the measure of angle M

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$M=\frac{1}{2}[arc\ AB+arc\ BC-arc\ AC]$

substitute

$M=\frac{1}{2}[2\gamma+2\alpha-2\beta]\\M=[\gamma+\alpha-\beta]$

step 3

Find the measure of angle N

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$N=\frac{1}{2}[arc\ AC+arc\ BC-arc\ AB]$

substitute

$N=\frac{1}{2}[2\beta+2\alpha-2\gamma]\\N=[\beta+\alpha-\gamma]$

step 4

Find the measure of angle P

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$P=\frac{1}{2}[arc\ AC+arc\ AB-arc\ BC]$

substitute

$P=\frac{1}{2}[2\beta+2\gamma-2\alpha]\\P=[\beta+\gamma-\alpha]$

5 0

3 years ago

The table shows the heights of 40 students in a class.

Studentka2010 [4]

Answer:

Step-by-step explanation:

Hello!

The given information is displayed in a frequency table, since the variable of interest "height of a student" is a continuous quantitative variable the possible values of height are arranged in class intervals.

To calculate the mean for data organized in this type of table you have to use the following formula:

X[bar]= (∑x'fi)/n

Where

x' represents the class mark of each class interval and is calculated as (Upper bond + Lower bond)/2

fi represents the observed frequency for each class

n is the total of observations, you can calculate it as ∑fi

Class marks:

x₁'= (120+124)/2= 122

x₂'= (124+128)/2= 126

x₃'= (128+132)/2= 130

x₄'= (132+136)/2= 134

x₅'= (136+140)/2= 138

Note: all class marks are always within the bonds of its class interval, and their difference is equal to the amplitude of the intervals.

n= 7 + 8 + 13 + 9 + 3= 40

X[bar]= (∑x'fi)/n= [(x₁'*f₁)+(x₂'*f₂)+(x₃'*f₃)+(x₄'*f₄)+(x₅'*f₅)]/n) = [(122*7)+(126*8)+(130*13)+(134*9)+(138*3)]/40= 129.3

The estimated average height is 129.3cm

This average value is estimated because it wasn't calculated using the exact data measured from the 40 students.

The measurements are arranged in class intervals, so you know, for example, that 7 of the students measured sized between 120 and 124 cm (and so on with the rest of the intervals), but you do not know what values those measurements and thus estimated a mean value within the interval to calculate the mean of the sample.

I hope this helps!

4 0

4 years ago

Someone please help me

Ugo [173]

Answer:

200

Step-by-step explanation:

idk really I just remember learning this

3 0

3 years ago

Read 2 more answers