56 would have a remainder of 2 using multiples of 3
56/3 = 18 remainder 2
56/6 = 9 remainder 2
56/9 = 6 remainder 2
56/18 = 3 remainder 2
56/27 = 2 remainder 2
Now divide 28 by the above numbers to see which ones have 1 as a remainder:
28/3 = 9 remainder 1
28/6 = 4 remainder 4
28/9 = 3 remainder 1
28/18 = 1 remainder 10
28/27 = 1 remainder 1
There are 3 numbers that will work.
Answer: c. 3
+18. A square root always has two answers, a positive and a negative
Answer:
-
Step-by-step explanation:
= ( cross- multiply )
6x = 5y ( divide both sides by 6 )
x = y
Then
← substitute x = y into the expression
=
=
=
= × -
= -
Answer:
theres no question, but i love your pfp
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Step-by-step explanation: