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3 years ago

two angles in a triangle mesaure 65 degrees and 75 degrees what is the measure of the third angle of the triangle

Mathematics

1 answer:

podryga [215]3 years ago

8 0

Answer:

40°

Step-by-step explanation:

The interior sum of a triangle is 180°. Since we have two known angles we will subtract those values from 180 to obtain our third angle and so:

180°-65°-75°=40°

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Can someone please help with these 2 questions? It would mean the world to me. I have attached the image for the questions.

sweet [91]

Answer:

2 $\frac{1}{20}$

Step-by-step explanation:

for question a)

It would be easier if you converted these to improper fractions (currently it is in the form of a proper fraction)

to convert to improper fraction, you would multiply the denominator (bottom no. of fraction) by the whole number , then add that with the numerator (top no. of fraction) and put the whole thing over the denominator.

E.g.

7 $\frac{1}{4}$ = 7x4 + 1 = 29

Thus, improper fraction would be $\frac{29}{4}$

do same thing for other one

thus , $\frac{26}{5}$

now,

$\frac{29}{4}$ - $\frac{26}{5}$

however, you can't do this as the denominators are not the same, so multiply them by a number which would give the a common denominator (20 would be the best option for common denominator)

$\frac{145}{20} -\frac{104}{20}$ = $\frac{41}{20}$

convert back to mixed number

2 $\frac{1}{20}$

5 0

3 years ago

Read 2 more answers

Thomas made 8700mL of tomato soup. He packed 1.6L of the soup in his kids' lunches. He then froze half of the remaining soup. Ho

Nitella [24]

Let's convert the 8700mL to L so that we can use the information in the problem more easily and swiftly. Since 1000mL is the same thing as 1L, we can say that 8700 mL of tomato soup is equal to 8.7L of tomato soup.

First, we know that he removed 1.6L to put in his kids' lunches. Thus, we now have 7.1L remaining. Now, we know that he froze half of this. Half of 7.1L is 3.55L (7.1L/2 = 3.55L), which means that he froze 3.55L. Finally, we will need to convert this back to mL. Since 1L is equal to 1000mL, we can multiply 3.55 by 1000 to get 3550mL.

5 0

4 years ago

The mean weight of 10 randomly selected newborn babies at a local hospital is 7.14 lbs and the standard deviation is 0.87 lbs. A

sergejj [24]

Answer:

a) $ME= 1.83 \frac{0.87}{\sqrt{10}}=0.5035$

b) 90% of all samples of size 10 have sample means within 0.5035 of the population mean.

c) The 90% confidence interval would be given by (6.636;7.643)

d) Yes, since the lower limit for the 90% confidence interval is higher than the value of 6.5 we can conclude that the true mean is significantly higher than 6.5 at 10% of significance. (6.636>6.5)

e) If we increase the confidence level that implies increase the margin of error. Since with more confidence level the value for the critical value $t_{\alpha/2}$ increase. So then the new interval would be wider than the original.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=7.14$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=0.87 represent the sample standard deviation

n=10 represent the sample size

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And the margin of error is given by:

$ME= t_{\alpha/2}\frac{s}{\sqrt{n}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,9)".And we see that $t_{\alpha/2}=1.83$

$ME= 1.83 \frac{0.87}{\sqrt{10}}=0.5035$

Part b

90% of all samples of size 10 have sample means within 0.5035 of the population mean.

Part c

Now we have everything in order to replace into formula (1):

$7.14-1.83\frac{0.87}{\sqrt{10}}=6.637$

$7.14+1.83\frac{0.87}{\sqrt{10}}=7.643$

So on this case the 90% confidence interval would be given by (6.636;7.643)

Part d

Yes, since the lower limit for the 90% confidence interval is higher than the value of 6.5 we can conclude that the true mean is significantly higher than 6.5 at 10% of significance. (6.636>6.5)

Part e

If we increase the confidence level that implies increase the margin of error. Since with more confidence level the value for the critical value $t_{\alpha/2}$ increase. So then the new interval would be wider than the original.

7 0

4 years ago

Determine the IQR for this set of data. 12, 13, 14, 15, 17, 18, 19, 19, 22, 23<br> 14 <br> 17.5

VladimirAG [237]

Answer:5

Step-by-step explanation:

4 0

3 years ago

Please help me question is in the picture

Sladkaya [172]

Answer:

1. Down

2. 9 units down

3. Left

4. 5 units left

7 0

3 years ago