You could turn the fraction into a decimal and then see which is bigger
The inequality that describes the possible values of the expression is:
<h3>What is the lower bound of values of the expression?</h3>
The expression is given by:
To find the lower bound, we try to see when the expression is negative, hence:
Applying cross multiplication and simplifying the 3's, we have that:
From the bounds given, this expression will never be true, at most they can be equal, when:
a = b = 4.
Hence the lower bound of values of the expression is of 0.
<h3>What is the upper bound of values of the expression?</h3>
The expression is a subtraction, hence we want to maximize the first term and minimize the second.
Considering that the first term is direct proportional to b and inverse to a, and the second vice versa, we want to:
Then:
Hence the bounds are:
More can be learned about values of expressions at brainly.com/question/625174
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4 = amount
<span>8 = base </span>
<span>amount / base = percent </span>
<span>4 / 8 = 0.50 </span>
<span>multiply 100 times the decimal and attact he % symbol </span>
<span>100 x 0.5 = 50 % </span>
<span>4 is 50% of 8 </span>
The hundredths place is where the 5 is.
Look to the right of the hundredths place and determine if the number is 5 or more or if the number is 4 or less.
In this problem, the number to the right of 5 is 1, and 1 is less than 4.
This means you can keep the 5 the same and every number after the 5 becomes imaginary zeroes.
3.95174 becomes 3.95 (rounded to nearest hundredth).
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
