What is 59% of 75? can some one help me please and thank u

Jordan had $10.00 if each drawing pen costs $1.49, how many can he buy

Nonamiya [84]

He can by 6 pens. 6.7 to be exact.

Hope this helps!!

7 0

3 years ago

The function f(x) = 7x-m/2-nx, find the values of m and n such that the vertical asymptote is x=6, and the x-intercept is 5.

Reil [10]

The function is f(x)= (7x-m)/(2-nx)
the vertical asymptote is x=6, that means 2/n = 6 or n=1/3

And now, we have f(x)=(7x-m):(2-1/3x)= (14x-2m): (6-x)

the x-intercept is 5 and we have y=0, x=5. So we obtain 0=(70-2m):(6-5)
or 70-2m=0, m=35

Conclusion m=35 and n=1/3

7 0

4 years ago

1) Write the equation parallel to the following equations that would go through (2,7):

myrzilka [38]

Note: Your option 'b' is somewhat ambiguous, so I am assuming you meant to write the equation y=2x+3 for the 'b' option.

Answer:

the equation y = 2x + 3 has slope m=2 and the y-intercept is 3, and also PASSES through the point (2, 7).

Step-by-step explanation:

An equation parallel to the given line equation will have the same slope.

Given the point (2, 7) from which the equation passes through.

so checking all the equations in the options to check whether any equation passes through or not.

Checking the option 'a':

y = 3x - 2

Putting (2, 7)

7=3(2)-2

7=6-2

7=4

L.H.S is not equal to R.H.S

Therefore, the option 'a' is NOT correct.

So, the equation y = 3x - 2 will NOT PASS through the point (2, 7)

Checking the option 'b':

y = 2x + 3

Putting (2, 7)

7=2(2)+2

7=7

L.H.S is equal to R.H.S

Therefore, option 'b' is the CORRECT option.

So, the equation y = 2x + 3 will PASS through the point (2, 7)

Checking the option 'c':

y = x-6

Putting (2, 7)

7=2-6

7=-4

L.H.S is not equal to R.H.S

Therefore, the option 'c' is NOT correct.

So, the equation y = x-6 will NOT PASS through the point (2, 7)

Checking the option 'd':

y + 2x = 8

Putting (2, 7)

7+2(2)=8

7+4=8

11=8

L.H.S is not equal to R.H.S

Therefore, the option 'd' is NOT correct.

So, the equation y + 2x = 8 will NOT PASS through the point (2, 7)

Therefore, considering the above analysis, we conclude that:

Option 'b' is the CORRECT option.

So, the equation y = 2x + 3 will PASS through the point (2, 7).

also

The slope-intercept form of the equation is

$y=mx+b$

where m is the slope and b is the y-intercept.

Therefore, the equation y = 2x + 3 has slope m=2 and the y-intercept is 3, and also PASSES through the point (2, 7).

5 0

3 years ago

What is the nth term rule of the quadratic sequence below?

Ahat [919]

Answer:

The nth term = n^2 - 2n - 3.

Step-by-step explanation:

Here, we will be finding the nth term of a quadratic number sequence. A quadratic number sequence has nth term = an² + bn + c

Example 1

Write down the nth term of this quadratic number sequence.

-3, 8, 23, 42, 65...

Step 1: Confirm the sequence is quadratic. This is done by finding the second difference.

Sequence = -3, 8, 23, 42, 65

1st difference = 11,15,19,23

2nd difference = 4,4,4,4

Step 2: If you divide the second difference by 2, you will get the value of a.

4 ÷ 2 = 2

So the first term of the nth term is 2n²

Step 3: Next, substitute the number 1 to 5 into 2n².

n = 1,2,3,4,5

2n² = 2,8,18,32,50

Step 4: Now, take these values (2n²) from the numbers in the original number sequence and work out the nth term of these numbers that form a linear sequence.

n = 1,2,3,4,5

2n² = 2,8,18,32,50

Differences = -5,0,5,10,15

Now the nth term of these differences (-5,0,5,10,15) is 5n -10.

So b = 5 and c = -10.

Step 5: Write down your final answer in the form an² + bn + c.

2n² + 5n -10

Example 2

Write down the nth term of this quadratic number sequence.

9, 28, 57, 96, 145...

Step 1: Confirm if the sequence is quadratic. This is done by finding the second difference.

Sequence = 9, 28, 57, 96, 145...

1st differences = 19,29,39,49

2nd differences = 10,10,10

Step 2: If you divide the second difference by 2, you will get the value of a.

10 ÷ 2 = 5

So the first term of the nth term is 5n²

Step 3: Next, substitute the number 1 to 5 into 5n².

n = 1,2,3,4,5

5n² = 5,20,45,80,125

Step 4: Now, take these values (5n²) from the numbers in the original number sequence and work out the nth term of these numbers that form a linear sequence.

n = 1,2,3,4,5

5n² = 5,20,45,80,125

Differences = 4,8,12,16,20

Now the nth term of these differences (4,8,12,16,20) is 4n. So b = 4 and c = 0.

Step 5: Write down your final answer in the form an² + bn + c.

5n² + 4n

5 0

3 years ago

HELPZZZZZZZ 25 PTSS and yes ik it is not math

zhannawk [14.2K]

13. Ignorance
14. Assistance
15. Importance
16. Performance
17. Distance
18. Absence
19. Attendance
(Hope this helps!!) Can I pls have a brainliest??

4 0

3 years ago

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