The vertices of triangle jkl are j(-2,1), k(2,-3), and l(2 2). The triangle is reflected over the line y=x. Graph triangle jkl a
nd triangle j’k’l’.
1 answer:
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Alright, lets get started.
We could use sine law to find the remaining angle.
Plugging the value of sin 64
Cross multiplying
sin S = 0.8189
Taking inverse on both side
S = 55° : Answer
Hope it will help :)