it is a rotation ........
Answer:
To find a
sin 30=a/6in
1/2=a/6in
2a=6in
a=6in/2
a=3in
To find b
cos 30=b/6in
/3/2=b/6in
2b=/3*6in
b=2/3(two radical three)
I don't get the radical sign so I use / sign on the last 3 steps on the second
Answer:
(LCM)
Step-by-step explanation:
Least common multiple = LCM
HOPE THIS HELPS :)
The amount of shampoo required by Morgan each week to bathe her dog = 2 oz
So
The amount of shampoo required by Morgan in 7 days to bathe her dog = 2 oz
The amount of shampoo remaining after 4 weeks = 34 oz
So the amount of shampoo remaining after (4 * 7) days = 34 oz
The amount of shampoo remaining after 28 days = 34 oz
The amount of shampoo that Morgan uses in 28 days = (2/7) * 28 oz
= 2 * 4 oz
= 8 oz
Then
8 oz of shampoo is required by Morgan in = 28 days
Then
34 oz of shampoo will be used in = (28/8) * 34 days
= 7 * 17 days
= 119 days
So
The total number of
days before the bottle becomes empty = 119 + 8 oz
= 127 days
Answer:
https://iepa.org.au/network-news/it
Step-by-step explanation:
that link is answer
