No. 3/10 X 100/1 = 300/10 = 30.
The answer is at least 6.
1a. 21/3+32/5
((2*3)+1)/3+((3*5)+2)/5
7/3+17/5
(7*5+17*3)/15
86/15
1b. 2/3+3/5+2/5
(2*5+3*3+2*3)/15
(10+9+6)/15
25/15
5/3
2a. 57/10-22/5
(5*10+7)/10-(2*5+2)/5
57/10-12/5
(57*1-2*12)/10
33/10
2b. 5/12-1/4
(5*1-1*3)/12
2/12
1/6
3 say she has x stamps,she gave 2/9 and 1/5 to her frends so she is left with
X-2x/9-x/5
(9*5x-5*2x-9*1x)/45
(45x-10x-9x)/45
26x/45
4. 7/10+1/5
(1*7+2*1)/10
9/10
5. Brick 21/3kg
Stone (2*3+1)/3-(1*10+1)/10
7/3-11/10
(7*10-3*11)/30
(70-33)/30
37/30
<span>On every type of factoring problem ALWAYS look first for a GCF, a greatest common factor. </span>
Answer:
A. True
B. True
C. False
D. True
Step-by-step explanation:
A) To find the probability of the letters spelling CAT go to the letter C, then A, and finally T. there is only one sequence that does this, so the numerator will be 1. There are 6 outcomes overall, so the denominator will be 6. The probability of the letters spelling CAT would be 1/6. The answer is true.
B) To find the probability of T being the first letter go to the letter T. All sequences after the letter T will all be included in the answer. TAC and TCA are both possible solutions, this means there are 2 correct outcomes, so 2 is the numerator. Again, there are 6 outcomes overall, so the denominator will be 6. The probability of T being the first letter is 2/6, which is equal to 1/3. The answer is true.
C) To find the probability of A being the first letter go to the letter A. All sequences after the letter A will all be included in the answer. ACT and ATC are both possible solutions, this mean there are 2 correct outcomes, so 2 is the numerator. Again, there are 6 outcomes overall, so the denominator will be 6. The probability of A being the first letter is 2/6. The answer is false.
D) To find how many total outcomes are possible go to the tree diagram and look to the far right. Go down each of the rows to find all of the outcomes, there is T,C,T,A,C, and A. That means there are six possible outcomes. The answer is true.
