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3 years ago

Please help me find the perimeter.

Mathematics

1 answer:

slavikrds [6]3 years ago

8 0

Answer:

31.42 cm (rounded up to two decimal places)

Step-by-step explanation:

We first find the circumference of the semi-circle segment:

The circumference will be given by; $\frac{1}{2}$ × π × D (where D is the diameter)

The diameter is 6 cm so circumference is;

$\frac{1}{2}$ × π × 6 cm = 9.42 cm (rounded up to two decimal places)

The perimeter of the figure therefore is;

8cm + 6 cm + 8 cm + 9.42 cm = 31.42 cm

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A cylindral drill with radius 5 cm is used to bore a hole through the center of a sphere with radius 9 cm. Find the volume of th

masya89 [10]

The volume of the ring-shaped remaining solid is 1797 cm³.

The volume is the total space occupied by an object.

The volume of a sphere of radius r units is given as (4/3)πr³.

The volume of a cylinder with radius r units and height h units is given as πr²h.

In the question, we are asked to find the volume of the remaining solid when a sphere of radius 9cm is drilled by a cylindrical driller of radius 5cm.

The volume will be equal to the difference in the volumes of the sphere and cylinder, where the height of the cylinder will be taken as the diameter of the sphere (two times radius = 2*9 = 18) as it is drilled through the center.

Therefore, the volume of the ring-shaped remaining solid is given as,

= (4/3)π(9)³ - π(5)²(18) cm³,

= π{972 - 400} cm³,

= 572π cm³,

= 1796.99 cm³ ≈ 1797 cm³.

Therefore, the volume of the ring-shaped remaining solid is 1797 cm³.

Learn more about volumes of solids at

brainly.com/question/14565712

#SPJ4

3 0

1 year ago

Help asap plsss ..lol

coldgirl [10]

Answer:

n = 3/7

Step-by-step explanation:

8 0

3 years ago

The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p

VLD [36.1K]

Answer:

$3.13$

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

$\chi^2_{1-\frac{\alpha}{2}}= 51.770$

Chi square critical value for upper tail =

$\chi^2_{\frac{\alpha}{2}}= 81.085$

80% confidence interval:

$\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}$

Putting values, we get,

$=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13$

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0

3 years ago

Help pls!!

hodyreva [135]

Answer:

C) 33 meters

Step-by-step explanation:

In this question, we need to find the value of the variable "x".

To do this, we must use the Pythagorean theorem: a² + b² = c²

Plug in your values and solve:

56² + b² = 65²

3,136 + b² = 65²

3,136 + b² = 4,225

Subtract 3,136 from both sides.

b² = 1,089

To cancel out the exponent, we would square root both sides.

√b² = √1,089

b = 33

This means that C) 33 meters will be your answer.

3 0

3 years ago

Read 2 more answers

Find the distance between (-3,5) and (4,-2)

Westkost [7]

Answer:

7√2 or approx. 9.89949

Step-by-step explanation:

distance between two points is

d=√(∆x^2+∆y^2)

where...

d is distance

∆x is change in x value

and ∆y is change in y value

In this problem ∆x=(-3)-4=(-7)

∆y=5-(-2)=7

plugging in those values gives us

d=√((-7)^2+7^2)

Solving this expression gives us

d=√(49+49)=√98

After simplifying the radical we are left with 7√2 or about 9.89949.

3 0

3 years ago

Please help me find the perimeter.​

Please help me find the perimeter.