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3 years ago

15

A dime has a diameter of about 18 millimeters . About how many millimeters long would a row of 34 dimes be?

1 answer:

qwelly [4]3 years ago

5 0

End-on-end you just add up 18 - 34 times

or

18 × 34 = 612 mm

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On Monday, Anya read 11 pages of a book in 30 minutes. On Tuesday, she read 18 pages in 45 minutes. Did Anya's reading speed inc

Genrish500 [490]

Yes
11 diveded by 30 equals 61%
30 divided by 45 equals 66%

the average of 61% and 66% is more then 50%

8 0

3 years ago

How many different four-person relay team can recover from a student

prohojiy [21]

Well, You have 4 students and 8 other students. If theres 8 people, this means theres 8 combinations possible. This means you do 8x4 and you get 32.

3 0

4 years ago

X - 7y - 10<br> - x - 7y + 10<br> x - 7y + 10<br> Find the quotient. (5x - 35y + 50) ÷ 5

weqwewe [10]

Answer:

Divide each term by 5, looking at the coefficients. The answer is x - 7y + 10

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Simplify: <br> <img src="https://tex.z-dn.net/?f=2%2F5%281%2F3x-15%2F8%29-1%2F3%281%2F2-2%2F3x%29" id="TexFormula1" title="2/5(1

expeople1 [14]

Answer:

$16/45x-11/12$

Step-by-step explanation:

$2/5(1/3x-15/8)-1/3(1/2-2/3x)\\= 2/15x-30/40-1/6+2/9x\\= 16/45x-11/12$

3 0

3 years ago

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The burning time of a very large candle is normally distributed with mean of 2500 hours and standard deviation of 20 hours. Find

dezoksy [38]

Answer: C.-1.5

Step-by-step explanation:

Given: The burning time of a very large candle is normally distributed with mean $(\mu)$ of 2500 hours and standard deviation $(\sigma)$ of 20 hours.

Let X be a random variable that represent the burning time of a very large candle.

Formula: $Z=\dfrac{X-\mu}{\sigma}$

For X = 2470

$Z=\dfrac{2470-2500}{20}\\\\\Rightarrow\ Z=\dfrac{-30}{20}\\\\\Rightarrow\ Z=\dfrac{-3}{2}\\\\\Rightarrow\ Z=-1.5$

So, the z-score they corresponds to a lifespan of 2470 hours. =-1.5

Hence, the correct option is C.-1.5.

7 0

3 years ago